Answer: I don't think you have to do something here. are there any choices?
Step-by-step explanation:
we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
It is 3out of 100 for your answer
Option B:
sin x = 1 is the equation represented by the intersection of the graph.
Solution:
The graph lies between -1 and 1 in y-axis.
x-axis of the graph is all real numbers.
The graph oscillates between -1 and 1 and a shape that repeats itself every 2π units.
That is the domain of the graph is all real numbers.
The range of the graph is [-1, 1].
It clearly shows that, it is the graph of sinx = 1.
Hence sin x = 1 is the equation represented by the intersection of the graph.
Option B is the correct answer.