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Wewaii [24]
3 years ago
14

Find the mistake made in the steps to solve the equation below.

Mathematics
2 answers:
inn [45]3 years ago
6 0

Answer:

The correct option is B) Step 3 is incorrect and should be x=\frac{10}{8}.

Step-by-step explanation:

Consider the provided equation.

6x-1=-2x+9

Step 1: Use addition property of equality.

8x-1=9

Step 2: Use addition property of equality.

8x=10

Step 3: Use Division property of equality.

x=\frac{10}{8}

Step 4: Now simplify.

x=\frac{5}{4}

Now, by comparing these steps with the provided image we can concluded that the step 3 is incorrect.

Thus, the correct option is B) Step 3 is incorrect and should be x=\frac{10}{8}.

IgorC [24]3 years ago
4 0

Answer:

B. Step 3 is incorrect, it should be x = 10/8

Step-by-step explanation:

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C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

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Solution:

Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

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Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

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Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

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probability that sum of cards 8 is and one of cards is 5

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p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

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<em>The result is -13</em>

<h2>Explanation:</h2><h2 />

Here we have the following addition problem:

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