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3 years ago

Find the mistake made in the steps to solve the equation below.

Mathematics

2 answers:

inn [45]3 years ago

6 0

Answer:

The correct option is B) Step 3 is incorrect and should be $x=\frac{10}{8}$ .

Step-by-step explanation:

Consider the provided equation.

$6x-1=-2x+9$

Step 1: Use addition property of equality.

$8x-1=9$

Step 2: Use addition property of equality.

$8x=10$

Step 3: Use Division property of equality.

$x=\frac{10}{8}$

Step 4: Now simplify.

$x=\frac{5}{4}$

Now, by comparing these steps with the provided image we can concluded that the step 3 is incorrect.

Thus, the correct option is B) Step 3 is incorrect and should be $x=\frac{10}{8}$ .

IgorC [24]3 years ago

4 0

Answer:

B. Step 3 is incorrect, it should be x = 10/8

Step-by-step explanation:

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Find the are of the circle below.

Tanya [424]

To find the area of the circle with diameter = 18 cm

We will use the formula:

$\text{Area of a cirlce = }\pi r^2$

where r= radius of the circle

From the quesion diameter = 18 cm

radius = diameter/2

radius = 18cm/2 = 9 cm

substituting r = 9cm into the formula

$Area\text{ of a circle = }\pi(9)^2$ $A\text{rea of the circle }=\text{ 81}\pi cm^2$

The above answer is when we are to leave the answer in terms of π

Otherwise if π is given to be 3.14 or 22/7 , we will simply substitute into the formula

That is given that π= 3.14

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7 0

1 year ago

Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

$\sqrt{11-2x}=\sqrt{x^{2}+4x+4}$

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

$\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}$

$\sqrt{25}=\sqrt{25}$

$5=5$ ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

$\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}$

$\sqrt{9}=\sqrt{9}$

$3=3$ ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

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