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ANTONII [103]
3 years ago
8

How to write "360.124" in expanded.and exponential​

Mathematics
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

360.124 in expanded and exponential form :

300+60+1/10+2/100+4/1000

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Graph the line y = kx +1 given that point M belongs to the line.<br> M(2, -7)
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Lol I like your da baby pfp.

Oh, and the answer is y = -4x + 1

Here’s the graph:

8 0
3 years ago
The area of a rectangular vegetable patch is 42 square meters. It is 7 meters long. How wide is it?
Lyrx [107]
42÷7=6 meters

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Which transformations will alter the location of the vertex?
VashaNatasha [74]

Answer:

reflection

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4 0
4 years ago
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}&#10;\\&#10;\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}&#10;\\&#10;\\=\frac{-42\pm \sqrt{1764}}{-19.6}&#10;\\&#10;\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}&#10;\\&#10;\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}&#10;\\&#10;\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would
maxonik [38]

Answer:  b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e.  135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137  ,

since  135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146  

since  135.8< 146 < 155.9

So , it is usual.

d. 155  

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0
3 years ago
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