Answer:
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec
Step-by-step explanation:
<u><em>The correct question is</em></u>
A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?
we have

so
For h(t)=100 ft
substitute in the equation and solve for x


The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
therefore
The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec
Answer:
answer is d.10
hope this helps
here are the multiple choice
A.
40%
B.
30%
C.
15%
D.
10%
My answer is B 14-6
please let me know if it is wrong
Answer:
19657
Step-by-step explanation:

Hope this helps!