Y(initial) = 9
V(initial) = 168
V(final) = 0
g(accel-grav) = 32 (in feet per second
squared)
Use the following equation:
V(final) = V(initial) + a(t)
Since this object is moving straight up and
down, a = -32
Enter the knowns into the equation
0 = 168 - 32t
32t = 168
t = 168/9.8
t = 5.25
Now that you know the time it takes to
reach it's maximum, use the general
kinematics equation to solve for final
distance:
y(final) = y(initial) + V(initial)(t) + (1/2)a
(t²)
y(final) = 9 + 168(5.25) + (1/2)(-32)
(5.25²)
= 9 + 882 - 441
= 450 feet
in log minus means divide
log 6 - log 3 = log (6÷3)
log 6 - log 3 = log 2
Answer:
x = 11
Step-by-step explanation:
(3x + 28) + (5x + 52) + ( 2x - 10) = 180
(3x + 5x + 2x) + (28 + 52 - 10) = 180
10x + 70 = 180
10x = 180 - 70
10x = 110
x = 11
Answer:
First degree
Step-by-step explanation:
