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1 year ago

7.) six hundred thousand forty nine and eleven thousandths how do I write in standard form

2 answers:

6 0

Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.

Step-by-step explanation:

DIA [1.3K]1 year ago

5 0

60049.0011 This should be the answer

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Question

Alekssandra [29.7K]

Answer:

$d=7.8\ g/cm^3$

Step-by-step explanation:

Given that,

The dimensions of a rectangular block = 4 cm x 2 cm x 1.5 cm

Mass, m = 93.6 g

We need to find the density of steel. We know that the density of an object is equal to the mass divided by volume. So,

$d=\dfrac{m}{V}\\\\d=\dfrac{93.6}{4\times 2\times 1.5}\\\\d=7.8\ g/cm^3$

So, the density of the steel is $7.8\ g/cm^3$ .

8 0

2 years ago

Find the measure of angle CED in the figure below. Enter only the number.

nikdorinn [45]

Answer:

∠ CED = 58°

Step-by-step explanation:

∠ CED and ∠ AED are adjacent angles and sum to 180° , then

∠ CED + 122° = 180° ( subtract 122° from both sides )

∠ CED = 58°

6 0

1 year ago

Read 2 more answers

A(n) ________ is both equilateral and equiangular?

bekas [8.4K]

I believe it was a rectangle I'm not sure test it out.

8 0

2 years ago

Read 2 more answers

2) The two rectangles shown are similar.

Citrus2011 [14]

Answer:

$6\ cm$

Step-by-step explanation:

First Rectangle:

$length(l_1)=24\ cm\\\\Width(b_1)=9\ cm$

Second Rectangle:

$length(l_2)=16\ cm\\\\Let\ Width=b_2\ cm$

$Since\ these\ two\ rectangles\ are\ similar\\\\\frac{l_2}{l_1}=\frac{b_2}{b_1}\\\\\frac{16}{24}=\frac{b_2}{9}\\\\16\times 9=24\times b_2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ cross\ multiplication\\\\b_2=\frac{16\times 9}{24}\\\\b_2=6\ cm$

5 0

2 years ago

Write 12x – 3y= –24 in slope-intercept form.

a_sh-v [17]

Answer: y=4x+8

Step-by-step explanation:

5 0

2 years ago