Question

What acceleration will result when a 12 N net force applied to a 3kg object? A 6kg object?

Answer 1

As per Newton's II law we know that

$F_{net} = ma$

here for the first case we know that

$F_{net} = 12 N$

m = 3 kg

now we will have

$12 = 3\times a$

$a = 4 m/s^2$

now for other case we will have

m = 6 kg

now we have

$12 = 6 \times a$

$a = 2 m/s^2$