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fredd [130]
3 years ago
8

A baseball is hit high into the upper bleachers of left field. Over its entire flight the work done by gravity and the work done

by air resistance, respectively, are:______
a. positive, positive
b. positive, negative
c. negative, postive
d. negavite, negavite
e. unknow since vital information is lacking
Physics
1 answer:
saul85 [17]3 years ago
6 0

Answer:

Explanation:

As the ball rises up, the gravitational force and the resistance force of air acts downwards and the displacement is upwards so the angle between the force and the displacement is 180°, thus, the work done by the gravitational force and the resistance force of air is negative. So, option (d) is correct.

You might be interested in
a 3.18-kg rock is released from rest at a height of 26.6 m. ignore air resistance and determine (a) the kinetic energy at 26.6 m
antiseptic1488 [7]

Answer:

(a) 0 J

(b) 828.96 J

(c) 828.96 J

(d) 828.96 J

(e) 0 J

(f) 828.96 J

Explanation:

Given:

Mass of the rock is, m=3.18\ kg

Initial height of the rock is, h_{i}=26.6\ m

Final height of the rock is, h_f=0\ m

Initial velocity of the rock is, v_i=0\ m/s(Rest)

Acceleration due to gravity is, g=9.8\ m/s^2

(a)

Initial kinetic energy is given as:

K_i=\frac{1}{2}mv_i^2

Plug in the given values and solve for 'K_i'. This gives,

K_i=\frac{1}{2}\times 3.18\times 0^2=0

Therefore, initial kinetic energy is 0 J.

(b)

Initial potential energy is given as:

U_i=mgh_i\\U_i=3.18\times 9.8\times 26.6=828.96\ J

Therefore, initial potential energy is 828.96 J.

(c)

Mechanical energy is equal to the sum of kinetic and potential energy. It is always a constant value. Therefore,

ME=K_i+P_i\\ME=0+828.96=828.96\ J

Therefore, mechanical energy at 26.6 m is 828.96 J.

(d)

Now, at the final height of 0 m, the decrease in potential energy will be equal to the increase in the kinetic energy. In other words, the potential energy at the start will be converted to kinetic energy at the bottom.

Therefore, kinetic energy at the 0 m is given as:

K_f=U_i=828.96\ J

(e)

Potential energy at the final height is given as:

P_f=mgh_f=3.18\times 9.8\times 0=0\ J

Therefore, final potential energy is 0 J.

(f)

Total mechanical energy is a constant and doesn't depend on the height.

So, total mechanical energy at 0 m is same as that at 26.6 m.

Total mechanical energy is 828.96 J.

8 0
4 years ago
A sled whose total mass with cargo is 30.0 kg rests on ice. The coefficient of static friction is 0.20 and the coefficient of ki
romanna [79]

when sled just start to move the force on the sled will be equal to the static friction

So here we need to find the value of static friction

We know that

m = 30 kg

\mu_s = 0.20

now we know that normal force on the block is counterbalanced by weight of the block

F_n = mg

F_n = 30*9.8

now in order to find the friction force we can use

F_s = \mu_s * F_n

F_s = 0.20 * 30 * 9.8

F_s = 59 N

so it requires 59 N of force to move the sled

5 0
3 years ago
Prompt how does melanin provide protection against skin cancer?
Wittaler [7]

Answer:

absorb , it absorbs it ...

4 0
3 years ago
Why are very high temperatures and pressures required for fusion to occur?
SashulF [63]

Answer:

b

Explanation:

7 0
3 years ago
A car travels 6 m north for 2 seconds and 8 m south for 5 seconds. What is the car's
Degger [83]
2 m/s. 6+8/2+5 = 14/7 = 2
8 0
2 years ago
Read 2 more answers
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