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irinina [24]
3 years ago
6

A form letter can be customized by using different fields in a __________.

Physics
2 answers:
Juli2301 [7.4K]3 years ago
8 0
The answer is C. Email
Kitty [74]3 years ago
7 0

Answer:

C) Email

Explanation:

A form letter is composed using standard documents and specific data including names and dates. The formats of writing form letter and email are similar to each other. Both contain subject line, a template, body of message, and salutation in their formats. Hence, C will be the right answer.

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Which of the following is true about the mass of an object?
Butoxors [25]
I believe it is the first one
5 0
3 years ago
A bar B made of some material is attracted by a magnet. Is the bar B magnetised ?​
Dvinal [7]

Answer:

No, it is not magnetized.

Explanation:

Bar B does not necessarily have to be magnetized before it can be attracted to a magnet. It just has to be a magnetic material such as Iron.

If bar B were magnetized, it could either be attracted or repelled by the magnet since this would depend on the side of the pole of bar B facing it.

Since we are not given any information about bar B other than it is attracted to the magnet, it is thus not magnetized.

7 0
3 years ago
One kind of baseball pitching machine works by rotating light and stiff rigid rod about a horizontal axis until the ball is movi
erastova [34]

Answer:

(a). The ball's centripetal acceleration is 16.17\times10^{2}\ m/s^2

(b). The magnitude of the net force is 232.9 N.

Explanation:

Given that,

Mass of baseball = 144 g

Speed = 81 mph = 36.2 m/s

Distance = 81 cm

(a). We need top calculate the ball's centripetal acceleration just before it is released

Using formula of centripetal acceleration

a=\dfrac{v^2}{r}

Where, v = speed

r  = radius

Put the value into the formula

a=\dfrac{(36.2)^2}{81\times10^{-2}}

a=1617.82\ m/s^2

a=16.17\times10^{2}\ m/s^2

(b). We need to calculate the magnitude of the net force that is acting on the ball just before it is released

Using formula of force

F=\dfrac{mv^2}{r}

Put the value into the formula

F=\dfrac{144\times10^{-3}\times(36.2)^2}{81\times10^{-2}}

F=232.9\ N

Hence, (a). The ball's centripetal acceleration is 16.17\times10^{2}\ m/s^2

(b). The magnitude of the net force is 232.9 N.

4 0
3 years ago
List the metric symbols from largest to smallest
Ray Of Light [21]

Answer:

nano.  

micro.  

milli.

centi.  

kilo.  

mega.

giga.

tera.

Explanation:

7 0
3 years ago
Read 2 more answers
The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi
Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which   describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}

Where,

B= Magnetic Field

l = length

\mu_0 = Vacuum permeability

\epsilon_0 = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}

Recall that the speed of light is equivalent to

c^2 = \frac{1}{\mu_0 \epsilon_0}

Then replacing,

B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}

B = \frac{r}{2C^2} \frac{dE}{dt}

Our values are given as

dE = 2150N/C

dt = 5s

C = 3*10^8m/s

D = 0.440m \rightarrow r = 0.220m

Replacing we have,

B = \frac{r}{2C^2} \frac{dE}{dt}

B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}

B =5.25*10^{-16}T

Therefore the magnetic field around this circular area is B =5.25*10^{-16}T

3 0
3 years ago
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