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hammer [34]
3 years ago
9

A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on

a level road?
Physics
1 answer:
MAXImum [283]3 years ago
3 0

Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

Ec=\frac{1}{2} *m*v^{2}

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}

W=\frac{1}{2} *m*(v2^{2}-v1^{2})

In this case:

  • W=?
  • m= 2,145 kg
  • v2= 12 \frac{m}{s}
  • v1= 25 \frac{m}{s}

Replacing:

W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})

W= -515,872.5 J

<u><em>The work required is -515,872.5 J</em></u>

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A wheel rotating with a constant angular acceleration turns through 19 revolutions during a 3 s time interval. Its angular veloc
Igoryamba

Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta  (1)

Where:

\omega_{f}: is the final angular velocity = 18 rad/s

\omega_{0}: is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

\omega_{f} = \omega_{0} + \alpha t

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

\omega_{0} = \omega_{f} - \alpha t   (2)

Now, by entering equation (2) into (1) we have:

\omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta                        

\omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta                              

(9\alpha)^{2} + 130.8 \alpha = 0  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

4 0
3 years ago
A rowboat passenger uses an oar to push the boat off the dock by exerting a force of 40N for 3.0s. What impulse acts on the boat
jarptica [38.1K]

Answer:

120 Ns

Explanation:

The impulse exerted on an object is given by:

I=Ft

where

F is the force applied

t is the time taken

In this problem, we have:

F = 40 N

t = 3.0 s

So, the impulse acting on the boat is

I=Ft=(40 N)(3.0 s)=120 Ns

8 0
3 years ago
In which direction does Earth’s gravitational force act?
dezoksy [38]
B downward
Earth's gravitational force acts in what direction? Earth's gravity acts downward toward the center of Earth. Gravity causes objects to accelerate downward, whereas air resistance acts in the direction opposite to the motion and reduces acceleration.
6 0
3 years ago
What is your average velocity if you drive a distance of 113 km at a speed of 47 km/h, then the same distance at a speed of 66 k
Sauron [17]

Answer:

V_{avg}=54.90\ km/h

Explanation:

Given that

Drive 113 km at 47 km/h and another 113 km at 66 km/h.

When distance is same then average velocity can be found by using below formula:

V_{avg}=\dfrac{2V_1V_2}{V_1+V_2}

Here

V_1= 47\ km/h

V_2= 66\ km/h

Now by putting the values

V_{avg}=\dfrac{2V_1V_2}{V_1+V_2}

V_{avg}=\dfrac{2\times 47\times 66}{47+66}

So

V_{avg}=54.90\ km/h

8 0
4 years ago
Read 2 more answers
What is a cosmic ray?
bonufazy [111]
Possibly something that interacts with the earth's magnetic field and produces the spectacular "Northern Lights", or "Aurora Borealis" if you prefer latin. Charged particles moving at relativistically high speeds, some of which may be from the sun via solar flares. I think that mu mesons are cosmic rays. First discovered by a scientist in a hot air balloon (he 'd gone up with instruments to detect them), and later used to verify the time dilation result of special relativity by MIT and the "mount washington experiment".
5 0
3 years ago
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