Since Kw= [H⁺][OH⁻], and the concentration of both substances are the same, the equation is now Kw=[H⁺]²
So,
3.31x10⁻¹³ = [H⁺]²
Take the square root= 5.75x10⁻⁷
Then take the negative log to find the pH:
-log(5.75x10⁻⁷) = 6.25
Umm. False i guess I don’t really know
This is the answer hope it helps you!!
Skeletal Equation
Ba(NO3)2 + KCl = BaCl2+ KNO3
Balanced equation
Ba(NO3)2 + 2KCl = BaCl2 + 2KNO3