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LiRa [457]
3 years ago
14

Which substance gets broken down in a homogeneous mixture? O colloid solution solute Osolvent​

Chemistry
1 answer:
astra-53 [7]3 years ago
3 0

Answer:

Solute

Explanation:

i just did the quiz

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Nataliya [291]

Answer:

(c) by increasing it's mass

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2 years ago
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33.56 g of fructose (C6H,206) and 18.88 g of water are mixed to obtain a 40.00 ml solution a. What is this solution's density? b
Darina [25.2K]

Explanation:

Mass of fructose = 33.56 g

Mass of water =  18.88  g

Total mass of the solution =  Mass of fructose + Mass of water = M

M = 33.56 g + 18.88  g =52.44 g

Volume of the solution = V = 40.00 mL

Density =\frac{Mass}{Volume}

a) Density of the solution:

\frac{M}{V}=\frac{52.44 g}{40.00 mL}=1.311 g/mL

b) Molar mass of fructose = 180.16 g/mol

Moles of fructose = n_1=\frac{ 33.56 g}{180.16 g/mol}=0.1863 mol

Molar mass of water = 18.02 g/mol

Moles of water= n_2=\frac{ 18.88 g}{18.02 g/mol}=1.0477 mol

Mole fraction of fructose in this solution:\chi_1

\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1863 mol}{0.1863 mol+1.0477 mol}

\chi_1=0.1510

Mole fraction of water = \chi_2=1-\chi_1=0.8490

c) Average molar mass of of the solution:

=\chi_1\times 180.16 g/mol+\chi_2\times 18.02 g/mol

=0.1510\times 180.16 g/mol+0.8490\times 18.02 g/mol=42.50 g/mol

d) Mass of 1 mole of solution = 42.50 g/mol

Density of the solution = 1.311 g/mL

d) Specific molar volume of the solution:

\frac{\text{Average molar mass}}{\text{Density of the mass}}

=\frac{42.50 g/mol}{1.311 g/mL}=32.42 mL/mol

5 0
3 years ago
Labels of many food products have expiration dates, at which point they are typically removed from the supermarket shelves. A pa
White raven [17]

Answer:

Explanation:

Since it first order, we use order rate equation

In ( \frac{A1}{A0}) = -kt where A1 is the final quality = 0.8 (80%), A0 is the initial quality = 1 ( 100%)

also, t half life = \frac{In2}{k} where k is rate constant

k = \frac{In 2}{45 days} = 0.0154

In ( \frac{0.8}{1}) = - 0.0154 t

-0.223 / -0.0154 = t

t = 14.49 approx 14.5 days from the date the yogurt was packaged

6 0
3 years ago
August kekule described the various ring structures of the carbon compound benzene. What type of chemist would he be considered
Andreyy89
B.  He would be considered an Organic Chemist since Organic Chemistry is the study of Carbon and its compounds.
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Which resonance structure would most likely create the infrared (IR) spectrum for the equilibrium geometry calculation of SCN −
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Resonance Structures for SCN-:[S-C N]-

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