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3 years ago

According to the arrhenius theory an acid is a substance that

Chemistry

2 answers:

8_murik_8 [283]3 years ago

6 0

Answer:

According to the theory, an Arrhenius acid is a substance that gives hydrogen ion, $H^{+}$ (or protons) as the only positively charged ions, when dissociated in water.

Explanation:

What this means is that acids increase the concentration of protons in water to form hydronium ions,as opposed to the idea that there aren't free hydrogen cations floating around in aqueous solution.

The Arrhenius definitions of acidity and alkalinity are restricted to aqueous solutions and refer to the concentration of dissolved ions.

Vsevolod [243]3 years ago

5 0

Answer:

An acid is a substance that releases H⁺ in aqueous solution.

Explanation:

There are different acid-base theories, such as Arrhenius, Bronsted-Lowry, Lewis, etc.

According to the Arrhenius theory, an acid is a substance that releases H⁺ in aqueous solution.

HCl(aq) → H⁺(aq) + Cl⁻(aq)

On the other hand, according to the Arrhenius theory, a base is a substance that releases OH⁻ in aqueous solution.

NaOH(aq) → Na⁺(aq) + OH⁻(aq)

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What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10

vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, $\rm pOH = 14 - pH$

The pH of KOH can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the first case, the concentration of the KOH is $1. 87 \times 10^{-13}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times 10^{-13}\;\rm M ]\\\\&= 12.73\end{aligned}$

Hence, the pH of KOH is 12.73.

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pOH of KOH can be calculated by the formula,

$\rm pOH = \rm -log [OH^{-}]$

The hydroxide concentration of the KOH solution is $5. 81 \times 10^{-3}\;\rm M$

Substituting value in the equation:

$\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm M ]\\\\&= 2.24 \end{aligned}$

Hence, the pOH of KOH is 2.24

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The pH of NaCl can be calculated by the formula,

$\rm pH = \rm -log [H^{+}]$

In the third case, the concentration of the NaCl is $1. 00\times 10^{-7}\;\rm M$

Substituting values in the equation:

$\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times 10^{-7}\;\rm M ]\\\\&= 7 \end{aligned}$

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

Learn more about pH and pOH here:

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3 0

2 years ago

True or false the si in sih4 does not follow the octet rule because hydrogen is in an unusual oxidation stat

ExtremeBDS [4]

The statement is true. The octet rule refers to the general rule of thumb wherein atoms of main-group elements tend to bond with other atoms in such a way that each atom possesses eight electrons (octet) in their valence shell. They tend to form the same electronic configuration as the noble gases. However, there are some exceptions to this rule. One of which is silane, SiH₄. A hydrogen atom only has 1 valence electron and needs another electron to complete its energy level. This is unlike other atoms, for example, carbon which has 4 valence electrons and needs to form 4 covalent bonds to fill its energy levels. Thus, 4 hydrogen atoms need only 4 more electrons. This is given by the silicon atom which has 4 valence electrons. Therefore, when a silicon atom is bonded to 4 hydrogen atoms, the resulting molecule, SiH₄, is a stable one.

6 0

2 years ago

How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution

Lelechka [254]

The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

<h3>Balanced equation </h3>

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 2
The mole ratio of the base, Ca(OH)₂ (nB) = 1

<h3>How to determine the volume of Ca(OH)₂ </h3>

Molarity of base, Ca(OH)₂ (Mb) = 1.48 M
Volume of acid, HCl (Va) = 36 mL
Molarity of acid, HCl (Ma) = 1.63 M
Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

2.96 × Vb = 58.68

Divide both side by 2.96

Vb = 58.68 / 2.96

Vb = 19.8 mL

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6 0

1 year ago

How many moles of gas are present when you collect 35.83 mL of the gas over water at 25.3°C and 0.97 atm?

Oksana_A [137]

Use Ideal Gas equation since values are given in Pressure (P), Volume (V), Temperature (T).
P V = n R T ; n= PV / RT
You can't use 1 mole= 22.4 L equation. Temperature and pressure values are not standard. ( 1 atm, 0

To choose the value of R ( gas constant), check out the units of other values in the equation. They are in atm,liter, kelvin, and mole. So, its value is 0.082 L atm/ K mol.

P= 0.97 atm
V= 35.83 * 10 ⁻³ L (conversion from ml to, just multiplied by 10 ⁻³ )
R= 0.082 L atm/ K mol
T= (25.3 + 273) K ( recall Kelvin = Celcius + 273; K= °C + 273<span>)
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Substitute values into equation of n= PV / RT

n= (0.97 atm) (35.83 * 10 ⁻³ L) / (0.082 L atm/ K mol) (298.3 K)= 0.014 mole

The answer is 0.014 mole

3 0

2 years ago

Read 2 more answers

I got the correct answer, but I don't know why. Could someone explain this to me?

MakcuM [25]

Answer:-

Option 2

Explanation:-

In a multi step reaction, the overall reaction is as fast as the slowest step only.

So the rate of a multistep reaction is the same as the rate of its slowest step.

The gas phase reaction was found to be second order wrt NO2.

So the slowest step must have 2 NO2 since the dependence is second order on NO2.

It was also found to be zero order wrt CO.

So the slowest step must not contain any CO since it’s presence has no effect on the reaction (zero order).

Among all options, only number 2 meets the two criterion

Thus the steps are

NO2 + NO2 – NO3 + NO (Slow)

NO3 + CO – NO2 + CO2 (Fast)

3 0

3 years ago