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agasfer [191]
3 years ago
12

What are the solutions of -x^2 -2=0

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

2^{1/2}*i, - 2^{1/2}*i

Step-by-step explanation:

       

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The sum of two consecutive integers is 471.<br><br> what is the equation
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Answer:

x+(x+1)=471

Step-by-step explanation:

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Which expression is the same as 10÷4?
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The answer would be D because when you divide 10 by 4 you take one fourth out of ten
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Segment addition postulate <br><br> Find PQ
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Answer:

PQ = 4

Step-by-step explanation:

As ; PQ=QR

PR = 8

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SO ; PQ = 4 , QR = 4

I hope I helped you^_^

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Simplify: (-2)(-3)+(4)(-8)<br><br>Simplify: (3)(-6)-18​
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4

Step-by-step explanation:

5 0
3 years ago
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The product of two consecutive odd intergers is 1 less than four times thier sum. Find the two integers.
seraphim [82]
Consecutive odd integers are 2 apart
they are x and x+2
the product (x times (x+2)) is 1 less than  4 times their sum

x(x+2)=-1+4(x+x+2)
x^2+2x=-1+4(2x+2)
x^2+2x=-1+8x+8
x^2+2x=8x+7 minus (8x+7) from both sides [tex]x^2-6x-7=0
factor
what  numbers multliply to get -7 and add to get -6?
-7 and 1
(x-7)(x+1)=0
set equal to 0
x-7=0
x=7

x+1=0
x=-1

so the x can be 7 or -1
the other number (x+2) can be 7 or 1

test each

7 and 9
7(9)=-1+4(7+9)
63=-1+4(16)
63=-1+64
63=63
true


-1 and 1
-1(1)=-1+4(-1+1)
-1=-1+4(0)
-1=-1+0
-1=-1
true



the 2 integers can be 7 and 9 or -1 and 1 (both pairs of numbers work)
3 0
3 years ago
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