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ollegr [7]
3 years ago
14

Yall hmu up on discord treshawn478#8007

Mathematics
2 answers:
MaRussiya [10]3 years ago
6 0

Answer:

. ╭─────╮

╭│...╭────╮

││...╰────╯

││...................│

╰│....╷─┌....│

....╰─╯... ╰─╯ඞ

Papessa [141]3 years ago
5 0

Answer:

Yaaaaass

Step-by-step explanation:

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Gavin's dog had a litter of puppies. All of the puppies in this litter were either yellow or black. If there was one less black
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Answer:

Total number of puppies in the litter = 11

Step-by-step explanation:

Let the number of yellow puppies in the litter = y

And the number of black puppies in the litter = b

If there was one less black puppy, ratio of yellow to black puppies = \frac{2}{3}

\frac{y}{b-1}=\frac{2}{3}

2(b - 1) = 3y

3y - 2b = -2 -----(1)

If there was one more black puppy, ratio of yellow puppies to black puppies = \frac{1}{2}

\frac{y}{b+1}=\frac{1}{2}

2y = b + 1

2y - b = 1 -------(2)

Equation (1) - 2× equation (2)

(3y - 2b) - 2(2y - b) = -2 - 2

3y - 4y - 2b + 2b = -4

y = 4

From equation (1),

3×4 - 2b = -2

12 - 2b = -2

-2b = -14

b = 7

Total number of puppies in the litter = 7 + 4 = 11

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