The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer: 5/3
Step-by-step explanation:
(3/5)x = 12
(5/3)(3/5)x = (5/3)12
x = 20
Therefore, choose Option D: 5/3
Hope I helped! <3
Answer:
Answer is 71.95°
Step-by-step explanation:
Cosine formula is
a^2=b^2+c^2-2bc(cosA)
cos A =b^2+c^2-a^2/2bc
if a= 119,b=94,c=173
cos A=94^2+173^2-119^2/2(94*173)
=8836+29,929-14,161/2(16,262)
=38765-14,161/32,524
=24604/32,524
=0.7564
cos A=0.7564
cos^-1=40.85°.that's for angle A.
Using the same formula
B=31.1°
C=180-(40.85+31.1)
C=180-71.95
C=108.05
Since angle on a straight line is 180
therefore x is 71.95
Also the sum of angles A and B
Sry but that’s too much which one would you like help on
Answer:
5 m
Step-by-step explanation:
Find the total length of the shelf by adding together the lengths of the two boards:
1 1/2 + 3 1/2
= 5
So, the total length of the shelf is 5 m
