All categories

3 years ago

What is the area? (IXL)

Mathematics

1 answer:

fiasKO [112]3 years ago

5 0

The middle section is a 4 by 4 square. Area = 4 x 4 = 16 square meters

The two outside triangles would form a rectangle 3 by 4. Area = 3 x 4 = 12 square meters

Total area = 16 + 12 = 28 square meters.

You might be interested in

Evaluate the indefinite integral.

eduard

Answer:

I believe its C , i took this class

Step-by-step explanation:

6 0

2 years ago

The following data set has a mode of 3, a mean of 10, and a median of 5.5. Which of these three measures gives the best idea of

ANTONII [103]

For this particular data set, the median most accurately represents the values present in the data set because most of the values are clustered close to it.

4 0

3 years ago

Read 2 more answers

What do you do with fractions in finding absolute value

Furkat [3]

Absolute value only removes the negative signs. Just multiply the numerator and the denominator

4 0

3 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago

What are 5 consecutive even integers that add up to 0

ale4655 [162]

$2a,2a+2,2a+4,2a+6,2a+8\\\\
2a+2a+2+2a+4+2a+6+2a+8=0\\\\
10a+20= 0\ \ \ \ | subtract\ 20\\\\
10a=-20\ \ \ \ | divide\ by\ 10\\\\
a=-2\\\\
Numers\ are: \ -2,0,2,4,6.$

4 0

3 years ago

Read 2 more answers