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3 years ago

Please factorise this question and show the entire process.

Mathematics

2 answers:

Alex Ar [27]3 years ago

5 0

Here, just we have take common of them.

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

dlinn [17]3 years ago

4 0

Answer:

3(x^4+324y^4)

Step-by-step explanation:

You can take out a 3 since 972 and 3 are both divisible by 3.

Therefore, 3(x^4+324y^4)

I hope this helped and have a good rest of your day!

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3 years ago

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Algebraic equation of 185 is less than a number

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3 years ago

Verify cot x sec^4x=cotx +2tanx +tan^3x

Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { 2\tan}^{2} x + { \tan}^{4} x)$

We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$

Cancel common factors:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}$

This finally gives:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

3 0

3 years ago

Which expression is equivalent to (5^-2)(5^-1) A. -1/125 B. -1/5 C. 1/125 D. 1/5

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Answer:

1/125

Step-by-step explanation:

(5^-2)(5^-1) = 5^-3=1/5^3=1/125

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3 years ago

Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers away. It takes Amy 40 minutes t

ruslelena [56]

Bill and Amy travel the same distance from home to school of 14.4 kilometers. Amy takes 40 minutes of time to arrive to school which means she has a rate of 14.4 km /40 minutes or 6 meters/ second. Bill takes a total 60 minutes to arrive to school. Hence Bill's rate is equal to 14.4 km/60 minutes or 4 meters/ second.Amy's is 2 m/s faster than Bill's speed, then.

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2 years ago

Please factorise this question and show the entire process.​

Please factorise this question and show the entire process.