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Crazy boy [7]
3 years ago
8

Please factorise this question and show the entire process.​

Mathematics
2 answers:
Alex Ar [27]3 years ago
5 0

Here, just we have take common of them.

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment

dlinn [17]3 years ago
4 0

Answer:

3(x^4+324y^4)

Step-by-step explanation:

You can take out a 3 since 972 and 3 are both divisible by 3.

Therefore, 3(x^4+324y^4)

I hope this helped and have a good rest of your day!

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Geometry 7.2 puzzle time where did columbus land when he found america
kobusy [5.1K]

Answer:

Plymouth Rock

Step-by-step explanation:

he landed in plymouth

7 0
3 years ago
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Algebraic equation of 185 is less than a number
kkurt [141]

Answer:

n-185

Step-by-step explanation:

since 185 needs to be subtracted from a number, or n

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3 years ago
Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
Which expression is equivalent to<br> (5^-2)(5^-1)<br> A. -1/125<br> B. -1/5<br> C. 1/125<br> D. 1/5
n200080 [17]

Answer:

1/125

Step-by-step explanation:

(5^-2)(5^-1) = 5^-3=1/5^3=1/125

3 0
3 years ago
Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers away. It takes Amy 40 minutes t
ruslelena [56]
Bill and Amy travel the same distance from home to school of 14.4 kilometers. Amy takes 40 minutes of time to arrive to school which means she has a rate of 14.4 km /40 minutes or 6 meters/ second. Bill takes a total 60 minutes to arrive to school. Hence Bill's rate is equal to 14.4 km/60 minutes or 4 meters/ second.Amy's is 2 m/s faster than Bill's speed, then. 
8 0
2 years ago
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