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sweet-ann [11.9K]
3 years ago
15

Which of the equations below represents the correct BALANCED equation?

Chemistry
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

b. Mg (s) + 2HCl (aq) --> MgCl2 (aq) + H2

Explanation:

A subscript applies only to the element it is attached to while coefficients apply to all elements in a compound.

"a" has 1 atom of each element on the left but 2 Cl on the right.

"c" has 2 Mg, 1 H, & 1 Cl on the left but 1 Mg, 2 H, and 2 Cl on the right.

"d" has 2 atoms of each element on the left but only 1 Mg on the right.

"b" is the only answer with equal numbers of atoms on the right and left sides of the equation.

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begging u to answer Which is not an inter molecular force? Select one: a. Inter atomic bonds b. van der waals forces c. hydrogen
Elenna [48]

Answer:

a-Interatomic bonds

Explanation:

First of all, it is not a force. Let alone be molecular force.

6 0
3 years ago
Calculate the volume occupied by 272g
cupoosta [38]

The answer for the following problem is mentioned below.

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

Explanation:

Given:

mass of methane(CH_{4}) = 272 grams

pressure (P) = 250 k Pa =250×10^3 Pa

temperature(t) = 54°C =54 + 273 = 327 K

Also given:

R = 8.31JK-1 mol-1 ,

Molar mass of  methane(CH_{4}) = 16.0​  grams

We know;

According to the ideal gas equation,

<u><em>P × V = n × R × T</em></u>

here,

n = m÷M

n =272 ÷ 16

<u><em>n = 17 moles</em></u>

Therefore,

250×10^3 × V = 17 × 8.31 × 327

V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

V = 184.78 × 10^-3 liters

<u><em>Therefore volume occupied by methane gas is  184.78 × 10^-3 liters </em></u>

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6 0
3 years ago
When lewis structures are drawn, do you only show valence electrons??
Lynna [10]
Yes you do cause its more explanation to
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8 0
3 years ago
How many milliliters of 2.00 M H2SO4 will react with 28.0 g of NaOH?
77julia77 [94]

Answer:175⋅mL of the given sulfuric acid

Explanation:

5 0
3 years ago
A binary compound created by reaction of bismuth and an unknown element E contains 52.07% Bi and 47.93% E by mass. If the formul
yulyashka [42]

Answer:

Atomic mass of E is 128.24

Explanation:

  • The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
  • In this case; the compound Bi₂E₃

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

            = (47.93 × 417.96 ) ÷ 52.07 %

            = 384.729

         E₃ = 384.729

Therefore; E = 384.729 ÷ 3

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The atomic mass of E is 128.24

6 0
3 years ago
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