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calculate the freezing point of 3.46 gram of a compound X in 160 gram of benzene when a separate sample of X was vaporized it's

Temka [501]

Answer: The freezing point of 3.46 gram of a compound X in 160 gram of benzene is $4.38^0C$

Explanation:

The relation of density and molar mass is:

$d=\frac{PM}{RT}$

where

d = density = 3.27 g/ L

P = pressure of the gas = 773 torr = 1.02 atm (760 torr = 1atm)

M = molar mass of the gas = ?

T = temperature of the gas = $116^0C=(116+273)K=389K$

R = gas constant = $0.0821Latm/Kmol$

$M=\frac{dRT}{P}=\frac{3.27g/L\times 0.0821Latm/Kmol\times 389K}{1.02atm}=102.3g/mol$

The relation of depression in freezing point with molality:

$\Delta T_f=k_f\times m$

$\Delta T_f$ = depression in freezing point = $T_f^0-T_f$ = $5.45-T_f$

$k_f$ = freezing point constant = 5.1

m = molality = $\frac{\text {moles of X}}{\text {weight of solvent in kg}}=\frac{3.46\times 1000}{102.3\times 160}=0.21$

$5.45-T_f=5.1\times 0.21$

$T_f=4.38^0C$

Thus the freezing point of 3.46 gram of a compound X in 160 gram of benzene is $4.38^0C$

5 0

2 years ago

Which of these is a chemical property of a substance?

valentinak56 [21]

Color, the other answers arent changing the substance into something different

3 0

3 years ago

"A group of college students believes that herbal tea has remarkable restorative powers. To test their belief, they visit a loca

Georgia [21]

D) the college students

Explanation:

In the experiment conducted by staffs of the nursing home, the group of college students that came for the experiment are the subjects of the experiment. A subject is a person that participates in a research.

In this research, the college students are the human participants in the experiment.
There must be a mutual agreement between the researcher and the subject because the subject is one that is being tested to see an outcome.
A subject can quit a research if he/she deems it fit at any time.

Learn more:

Experiments brainly.com/question/5096428

#learnwithBrainly

7 0

2 years ago

. Sulfur dioxide can be produced in the laboratory by the reaction of hydrochloric acid and a sulfite salt such as sodium sulfit

shutvik [7]

Answer:

Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g

Explanation:

SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.

the balanced chemical equation is as follows