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Radda [10]
3 years ago
8

6969696969696969696696969696969+333333333x3333333333333

Chemistry
1 answer:
solniwko [45]3 years ago
4 0

Answer:

my calculator said this

Explanation:

6.96969697E30

.

:0

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Potassium-40 decays to argon-40 with a half-life of 1.27 × 109 yr. The age of a mineral sample that has a mass ratio of 40ar to
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<u>Answer:</u> The age of the mineral sample is 1.09\times 10^9yrs

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The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

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t_{1/2} = half life of the reaction = 1.27\times 10^9yrs

Putting values in above equation, we get:

k=\frac{0.693}{1.27\times 10^9yrs}=5.46\times 10^{-10}yrs^{-1}

We are given:

Mass ratio of K-40 to Ar-40 = 0.812 : 1.00

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 5.46\times 10^{-10}yr^{-1}

t = time taken for decay process = ? yr

[A_o] = initial amount of the sample = [1.00 + 0.812] = 1.812 grams

[A] = amount left after decay process = 1.00 grams

Putting values in above equation, we get:

5.46\times 10^{-10}=\frac{2.303}{t}\log\frac{1.812}{1}\\\\t=1.09\times 10^9yrs

Hence, the age of the mineral sample is 1.09\times 10^9yrs

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