Question

Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N2(g)+3H2(g)⟶2NH3(g) Assume 0.100 mol N2 and 0.330 mol H2 are present initially. After complete reaction, how many moles of ammonia are produced?

Answer 1

Answer:

The number of moles of ammonia produced are 0.2 moles.

Explanation:

Given data:

Moles of N₂ = 0.100 mol

Moles of H₂  = 0.330 mol

Moles of NH₃ = ?

Solution:

First of all we will write the balance chemical equation

N₂  +  3H₂  → 2NH₃

Now we compare the moles of ammonia with nitrogen and hydrogen gas from balance chemical equation.

              N₂       :      NH₃

               1        :        2

            0.100   :       2/1 × 0.100 = 0.2 mol

                H₂        :      NH₃

                 3        :        2

                0.330  :      2/3× 0.330 = 0.22 mol

The number of moles of ammonia produced by nitrogen gas are less so nitrogen will be limiting reactant and number of moles of ammonia produced are 0.2 moles.