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BARSIC [14]
3 years ago
11

Select the correct statement (2.5 points) (A) Elements in the same row are similar in size. (B) Elements in the same column have

similar electronic and chemical properties (C) Both (A) and (B) (D) None of the above
Chemistry
2 answers:
Mrrafil [7]3 years ago
8 0

Answer:

B

Explanation:

We are talking about the periodic table in which elements where put under different rows and columns according to their atomic number (number of protons) in ascendant order.

In rows or periods we can find trends in some properties like atomic radius, electronegativity, etc...). So they are not similar in size. Option A is a false statement.

Also, they were organized in groups or columns according to their similar electronic configuration and chemical properties (like noble gases, halogens, etc...) This means option B is the correct statement.

mezya [45]3 years ago
5 0

Answer:

(B) Elements in the same column have similar electronic and chemical properties

Explanation:

The periodic table sorts the elements by their organization, it lists the elements in rows called periods and columns called groups or families, and in ascending order of their atomic numbers.

The horizontal lines in the periodic table are called periods and the vertical columns are called groups, and the electron and chemical properties of the elements in the same group are similar.

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A sample of gallium Bromide GaBr2,weighing 0.165 g was dissolved in water and treated with silver nitrate AgNO3, and resulting t
tresset_1 [31]

<u>Answer:</u> The percent gallium in gallium bromide is 30.30 %.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of gallium bromide = 0.165 g

Molar mass of titanium gallium bromide = 229.53 g/mol

Putting values in equation 1, we get:

\text{Moles of gallium bromide}=\frac{0.165g}{229.53g/mol}=0.00072mol

  • The chemical equation for the reaction of gallium bromide and silver nitrate follows:

GaBr_2+2AgNO_3\rightarrow 2AgBr(s)+Ga(NO_3)_2

By Stoichiometry of the reaction:

1 moles of gallium bromide produces 1 mole of gallium nitrate

So, 0.00072 moles of gallium bromide will produce = \frac{1}{1}\times 0.00072=0.00072moles of gallium nitrate

  • Now, calculating the mass of gallium nitrate from equation 1, we get:

Molar mass of gallium nitrate = 193.73 g/mol

Moles of gallium nitrate = 0.00072 moles

Putting values in equation 1, we get:

0.00072mol=\frac{\text{Mass of gallium nitrate}}{193.73g/mol}\\\\\text{Mass of gallium nitrate}=0.139g

Calculating the mass of gallium in the reaction, we use unitary method:

In 1 mole of gallium nitrate, 1 mole of gallium atom is present.

In 193.73 grams of gallium nitrate, 69.72 g of gallium atom is present.

So, in 0.139 grams of gallium nitrate, the mass of gallium present will be = \frac{69.72}{193.73}\times 0.139=g

  • To calculate the percentage composition of gallium in gallium bromide, we use the equation:

\%\text{ composition of gallium}=\frac{\text{Mass of gallium}}{\text{Mass of gallium bromide}}\times 100

Mass of gallium bromide = 0.165 g

Mass of gallium = 0.050 g

Putting values in above equation, we get:

\%\text{ composition of gallium}=\frac{0.050g}{0.165g}\times 100=30.30\%

Hence, the percent gallium in gallium bromide is 30.30 %.

3 0
3 years ago
I need your help!! about Chemistry (15 point!!)
irakobra [83]
1. I think it is true?
2. Low melting points
3. True
4. Atomic number, I think it’s periods?
5. Groups?


Sorry, I might not get all of them right :(


Hope this helps you in any way!!
6 0
3 years ago
Which of the following is a correct statement about collision theory?
rjkz [21]
The answer is D. Effective collisions lead to chemical reactions!
3 0
3 years ago
Read 2 more answers
Valence electrons are important because these are the only electrons involved with an atom's
Salsk061 [2.6K]
<span>Valence electrons are important because these are the only electrons involved with an atom's chemical reactivity.</span>
3 0
3 years ago
A metallurgist has one alloy containing 21% aluminum and another containing 42% aluminum. how many pounds of each alloy must he
Naily [24]
Answer is: 7.8 lb of 21% aluminum and 33.2 ib of <span>42% aluminum.</span>

ω₁<span> = 21% ÷ 100% = 0.21.
ω</span>₂<span> = 42% ÷ 100% = 0.42.
ω</span>₃<span> = 38% ÷ 100% = 0.38.
</span>m₁ = ?.

m₂<span> = ?.
</span>m₃ = m₁ + m₂<span>.
</span>m₃ = 41 pounds.

m₁ = 41 lb - m₂<span>.
ω</span>₁ · m₁ + ω₂ ·m₂ = ω₃ · m₃.

0.21 · (41 lb - m₂) + 0.42 · m₂ = 0.38 · 41 lb.

8.61 lb - 0.21m₂ + 0.42m₂ = 15.58 lb.

0.21m₂ = 6.97 lb.

m₂ = 6.97 lb ÷ 0.21.

m₂ = 33.2 lb.

m₁ = 41 lb - 33.2 lb.

m₁<span> = 7.8 lb.</span>



8 0
3 years ago
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