Answer:
mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g
Explanation:
The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula
K = concentration of X in ether/concentration of X in water
Partition coefficient, K(X) between ethoxy ethane and water = 40
Concentration of X in ether = mass(g)/volume(dm³)
Mass of X in ether = m g
Volume of ether = 50/1000 dm³ = 0.05 dm³
Concentration of X in ether = (m/0.05) g/dm³
Concentration of X in water = mass(g)/volume(dm³)
Mass of X in water left after extraction with ether = (5 - m) g
Volume of water = 1 dm³
Concentration of X in water = (5 - m/1) g/dm³
Using K = concentration of X in ether/concentration of X in water;
40 = (m/0.05)/(5 - m)
(m/0.05) = 40 × (5 - m)
(m/0.05) = 200 - 40m
m = 0.05 × (200 - 40m)
m = 10 - 2m
3m = 10
m = 10/3
m = 3.33 g of X
Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g
Answer:
Explanation:
Ionic compounds are electrically neutral because the charges of the cations and anions that make up the compound cancel each other out. In the case of salt for example, sodium has a charge of positive one, and chloride has a charge of negative one. Together, they neutralize the compound.
Answer:
B.
Explanation:
B. low temperature, high dissolved oxygen, and neutral pH
Hope this Helps.
Answer:
= C3H4N
Explanation:
We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.
We first calculate the number of moles of each element.
Carbon = 90g/12 g/mol
= 7.5 moles
Hydrogen = 11 g/ 1 g/mol
= 11 moles
Nitrogen = 35 g/ 14 g/mol
= 2.5 moles
The we get the mole ratio of the elements;
= 7.5/2.5 : 11/2.5 : 2.5 /2.5
= 3 : 4.4 : 1
= 3 : 4 : 1
Therefore;
The empirical formula will be; C3H4N
This is the electron configuration of neptunium:
<span>Rn 5f4 6d1 7s2
</span>or, if you want to complicate:
<span>1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f4 6d1
</span>Since there are 93 electrons, they make up 5f4 altogether.
