Ask question

Ask question

All categories

Delicious77 [7]

3 years ago

10

What is the domain and range for: y = arcsin(tanx)

1 answer:

Semmy [17]3 years ago

7 0

The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)

You might be interested in

Find the value of x ???????????? V

zalisa [80]

Step-by-step explanation:

By using formula of h^2=p^2+b^2

h=20

p=x

b=10

Now,

p=root h^2-b^2

x=root 20^2-10^2

x=root 400-100

x=root 300

x= 10root3

8 0

3 years ago

The volume of 10 drops of a liquid is 0.1 fluid ounce. What is the volume of 100 drops?

babunello [35]

10 * 0.1 = 1

100 drops is 1 fluid ounce.

7 0

3 years ago

A hotel wants to put a fence around a circular spa. The radius of the spa is feet. If the fence is built along the immediate edg

MariettaO [177]

For this case we must find the perimeter of the fence, in a circular way, knowing that the perimeter of a circle is given by:

$P = 2 \pi*r$

Where "r" represents the radius of the circle, in this case $r = \frac {5} {\sqrt {2} -1}$

Substituting in the perimeter equation we have:

$P = 2 \pi * \frac {5} {\sqrt {2} -1}$

Rationalizing we have:

$P = \frac {2 \pi * 5 (\sqrt {2} +1)} {(\sqrt {2} -1) * (\sqrt {2} +1)}\\P = \frac {2 \pi*5 \sqrt {2} +2 \pi*5} {2-1}\\P = 10 \pi \sqrt {2} +10 \pi$

Taking out common factor $\pi$ :

$P = (10 \sqrt {2} +10) \pi$

Answer:

$P = (10 \sqrt {2} +10) \pi\ feet$

Option C

3 0

3 years ago

The cone has a diameter of 8 meter and a hieght of 3 meters

Otrada [13]

Cool. Is there a question though

3 0

3 years ago

4 points 12. Michael has been assigned to read 75 pages from his library book this week. He has read 40 of these pages so far. W

Pachacha [2.7K]

Answer: 53 1/3%

hope this helps! :)

6 0

3 years ago