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ycow [4]
3 years ago
11

If pressure is increased from 200 kPa to 300 kPa, and the original volume of gas was 1.5 L, what is the new volume? Assume the t

emperature and number of particles are constant.
a. 0.5 L
b. 1 L
c. 2 L
d. 3 L
Physics
1 answer:
Oxana [17]3 years ago
6 0

Answer:

The answer to your question is:      V2 = 1 l

Explanation:

Data

P1 = 200 kPa

P2 = 300 kPa

V1 = 1.5 l

V2 = ?

Formula

                          P1V1 = P2V2

                          V2 = (P1V1) / P2

                          V2 = (200 x 1.5) / 300

                          V2 = 1 l

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A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are
igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

T = I\alpha = 0.303*0.6454 = 0.196 Nm

So the force acting on the other end to generate this torque mush be:

F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N

4 0
3 years ago
Why does it take more force to push a car than it takes to push a bicycle? Please fully explain
never [62]
The car mas more mass than a bicycle. Newton's second law states force equals mass times acceleration.
6 0
3 years ago
A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total
Rudik [331]

Answer:

a) 0.41 m/s

b) 0.51 m/s

Explanation:

(a)

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (15.4) + (93.1 - 0.292) V'

V' = 0.41 m/s

b)

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = - 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (- 15.4) + (93.1 - 0.292) V'

V' = 0.51 m/s

6 0
3 years ago
What is the answer to this?
pentagon [3]

Answer:

B

Explanation:

4 0
3 years ago
Read 2 more answers
The electrostatic force between two small charged particles is 5.2 x 10^-7 N at a distance of 2 meters. What will be the new for
Kamila [148]

Answer:

F_2=1.3\times 10^{-7}\ N

Explanation:

Given that,

Initial force, F=5.2\times 10^{-7}\ N

distance, d = 2 m

New distance, d' = 4 m

We need to find the new force. The electrostatic force between two charges is given by :

F=k\dfrac{q_1q_2}{d^2}

So,

\dfrac{F_1}{F_2}=(\dfrac{d_2}{d_1})^2\\\\\dfrac{F_1}{F_2}=(\dfrac{4}{2})^2\\\\\dfrac{F_1}{F_2}=4\\\\F_2=\dfrac{F_1}{4}\\\\F_2=\dfrac{5.2\times 10^{-7}}{4}\\\\F_2=1.3\times 10^{-7}\ N

So, the new force is equal to 1.3\times 10^{-7}\ N.

8 0
3 years ago
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