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lawyer [7]
3 years ago
15

A hydrogen fuel cell supplies power for a small motor. the fuel cell delivers a current of 0.5 a and a voltage of 0.43 v. what i

s the power supplied to the motor by the fuel cell?
Physics
1 answer:
Alexandra [31]3 years ago
3 0
<span>the power supplied to the motor by the fuel cell is 0.31 watts.
</span>
The current , I is 0.5 A.
Voltage, V is 0.43 V

From ohm's law: V = IR 
Thus, R = 0.43/0.5 = 0.86Ω

Now, Power = I^{2}R
                     = 0.5 ×0.5×0.86
                     = 0.215 W
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A constant force of 8.0 N is exerted for 4.0 s on a 16-kg object initially at rest. The change in speed of this object will be:
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8 0
3 years ago
where σ(t) and σ(0) represents the time-dependent and initial (i.e., time =0) stresses, respectively, and t and τ denote elapsed
lesya [120]

Answer:

E_r(6)=4.35614\ MPa

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\epsilon = Strain = 0.49

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\sigma=\sigma _0exp\left(-\frac{t}{\tau}\right)

at t = 32 s

0.41=3.1exp\left(-\frac{32}{\tau}\right)\\\Rightarrow exp\left(-\frac{32}{\tau}\right)=\frac{0.41}{3}\\\Rightarrow -\frac{32}{\tau}=ln\frac{0.41}{3}\\\Rightarrow \tau=-\frac{32}{ln\frac{0.41}{3}}\\\Rightarrow \tau=16.0787\ s

The time independent constant is 16.0787 s

E_{r}(t)=\frac{\sigma(t)}{\epsilon_0}

At t = 6

\\\Rightarrow E_{r}(6)=\frac{\sigma(6)}{\epsilon_0}

From the first equation

\sigma(t)=\sigma _0exp\left(-\frac{t}{\tau}\right)\\\Rightarrow \sigma(6)=3.1exp\left(-\frac{6}{16.0787}\right)\\\Rightarrow \sigma(6)=2.13451

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E_r(6)=4.35614\ MPa

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