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eduard
3 years ago
14

There are 20 children in the cast of a class play, and 8 of the children are boys. Of the boys, 4 have a speaking part in the pl

ay, and of the girls, 8 do not have a speaking part in the play. If a child from the cast of the play is chosen at random, what is the probability that the child has a speaking part?
a)2/5
b)1/2
c)3/5
d)3/4
Mathematics
2 answers:
denpristay [2]3 years ago
4 0

Answer:

A0 2/5

Step-by-step explanation:

First, find out how many girls there are by subtracting 8 (boys) from 20 (total). This means there are 12 girls. Since 8 girls aren't speaking, 4 are. 4+4=8. 8 out of the 20 children are speaking/ 8/20 simplified is 2/5

nikdorinn [45]3 years ago
3 0

Answer: The answer is option A

Step-by-step explanation: the probability that a boy has a speaking part is 4/20

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Now all you have to do is add these two numbers together then divide by 2 which will give you 34.

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3 0
2 years ago
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The ratio of games won at to the games lost for a basketball team is 3:2. The team won 18 games. How many games did the team los
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The easiest way to go about this is to divide the actual number of wins (18) by its corresponding element in the ratio.

So:

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7 0
3 years ago
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<u>Explanation: </u>

Let length = l ,

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