Answer:
<u>The correct answer is r = ∛GM*T²/4π²</u>
Step-by-step explanation:
Let's rewrite the formula to find the period of orbit of a satellite around a planet, to solve for r, this way:
T^2=(4pi^2/GM)r^3
T² = (4π²/GM) * r³
r³ = T²/ (4π²/GM)
r³ = T² * GM/4π²
r³ = GMT²/4π²
∛r³ = ∛GM*T²/4π²
r = ∛GM*T²/4π²
100/100'000*5 = 5000 + base commission of 100'000 = 105'000
Divide two from each side and get Y=10
y=10
