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e-lub [12.9K]
3 years ago
8

Can someone please help me on Carnegie??

Mathematics
1 answer:
alexdok [17]3 years ago
7 0

Answer:

First tell me what's Carnegie

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Can someone please help me with these two questions! :( ill mark u as brainlest
Maslowich

Answer:

1.A by SSS axiom

2.F as angle A is 62*

4 0
3 years ago
What is the value of x in the equation 2x + 9 = 21?<br> O2<br> 06<br> 09<br> O 15
Taya2010 [7]

Answer:

the answer is 6

Step-by-step explanation:

2x + 9 = 21

2x = 21 - 9

2x = 12

x = 6

4 0
2 years ago
Gronala costs $4.50 per pound. Assorted nuts cost $7.00 per pound. how many pounds of granola and nuts are needed to make 7 poun
yulyashka [42]

Let G be the granola we need (in pound)

Let N be the nut we need (in pound)

Trail mix cost $5.00 per pound---> cost for 7 pound = 5 x 7 = $ 35

4.5G+7N= 35

G+ N = 7

Therefore G = 5.6 N=1.4, we would need 5.6 pound granola & 1.4 pound nut

7 0
3 years ago
Read 2 more answers
What are the measures of Angles a, b, and c? Show your work and explain your answers.
jolli1 [7]
Answer: a = 40, b = 50, c = 115

Solution:
a = 40 (the vertical angles are equal)

b = 180 - 40 - a = 50 (the sum of interior angles of triangle is 180)

c = 180 - 65 = 115 (the linear theorem)
5 0
2 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

3 0
3 years ago
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