Answer:
the populations from which the samples were drawn have different standard deviations
Step-by-step explanation:
Given that the assumption of homogeneity of variance is the same as the assumption of the independent samples t-test which asserted that all comparison groups possess the same variance
Therefore, if the homogeneity of variance assumption is violated in an independent groups t-test, this means "the populations from which the samples were drawn have different standard deviations."
I would plug in each of the solutions to every equation and see which one works. This is probably easier than solving for x, y, and z. But let me know if you would like me to run through the steps!
First choice: using the first equation, -3(-3)-4(4)+6=-19 not -1 as listed. False.
Second choice: using the first equation, -3(4)-4(-3)+(-1)=-1 ; using the second equation, 2(4)+(-3)-(-1)=6 not -8 as listed. False.
Third choice: using the first equation, -3(-3)-4(4)+8=-17 not -1 as listed. False.
Fourth choice: using the first equation, -3(3)-4(-4)+-(-6)=-1 ; using the second equation,
2(3)+(-4)-(-6)=8 ; using the third equation, 3+8(-4)-(-6)=23
So the answer should be the fourth choice. Hope this helps! :)
The answer I believe would be C.
5x - 2 < 10
+ 2
5x < 12
÷ 5
x < 2.4
Hope this helped!
Answer:
To get the Least Common Multiple (LCM) of 12 and 46 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:
12:
2
2
3
46:
2
23
LCM:
2
2
3
23
The Least Common Multiple (LCM) is: 2 x 2 x 3 x 23 = 276
Step-by-step explanation: