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tatyana61 [14]
3 years ago
8

Some hardware can be added to the computer without having to restart or power down the computer. After a short period of time th

e device driver automatically loads and the hardware is available to applications and the user. This type of hardware is considered compatible with what type of technology?
Computers and Technology
1 answer:
faltersainse [42]3 years ago
8 0

Answer:

Plug and play technology

Explanation:

Plug and play technology also know as PnP allows user to directly connect devices to a computer and start using inmediatly. Other way user must have to search and install drivers for each component.

Usually PnP comes for regular use devices like: Keyboards, mouses, flashmemories, cameras, and others

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If you have a field that needs a unique number that's one greater than the last field entry, what field type would you typically
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AutoNumber it can do it all alone and put the number(If you don’t know the number to put).
4 0
3 years ago
Define a class named ComparableSquare that extends Square (defined above) and implements Comparable. Implement the compareTo met
Alexxx [7]

Answer:

/*********************************************************************************

* (The ComparableCircle class) Define a class named ComparableCircle that        *

* extends Circle and implements Comparable. Draw the UML diagram and implement   *

* the compareTo method to compare the circles on the basis of area. Write a test *

* class to find the larger of two instances of ComparableCircle objects.         *

*********************************************************************************/

public class Exercise_13_06 {

/** Main method */

public static void main(String[] args) {

 // Create two instances of ComparableCircle objects

 ComparableCircle comparableCircle1 = new ComparableCircle(12.5);

 ComparableCircle comparableCircle2 = new ComparableCircle(18.3);

 // Display comparableCircles

 System.out.println("\nComparableCircle1:");

 System.out.println(comparableCircle1);

 System.out.println("\nComparableCircle2:");

 System.out.println(comparableCircle2);

 // Find and display the larger of the two ComparableCircle objects

 System.out.println((comparableCircle1.compareTo(comparableCircle2) == 1  

  ? "\nComparableCircle1 " : "\nComparableCircle2 ") +  

  "is the larger of the two Circles");

}

}

3 0
3 years ago
10 sentences about computer parts.
Ahat [919]
One computer part is the CPU, it’s a piece of hardware the last allows your computer to access and interact all the applications and programs. The first ever CPU chip was invented around 4 decades ago. The keyboard is another computer part and it allows the user to type letters and numbers. There are about 104 keys on a keyboard and there are different parts in it. Some of the parts include, control keys, function keys, navigation keys, numeric keypad, and so on. A mouse is another device used with the keyboard to position the cursor. It’s a hand held device that detects two-dimensional motion relative to a surface. This motion is typically translated Into the motion of a pointer on a display, which allows a smooth control of the graphical user. Memory is a device to store all of your information and saved data. The motherboard is the backbone that tied together the computers components at one spot.
6 0
2 years ago
Match the expenses to their respective categories.
satela [25.4K]
Lambo , vacation and lavish weddings in want the other two in needs
4 0
3 years ago
Read 2 more answers
Two communicating devices are using a single-bit even parity check for error detection. The transmitter sends the byte 10101010
icang [17]

Answer:

The receiver will not detect the error.

Explanation:

The byte sent by transmitter: 10101010

The byte received by receiver due to channel noise: 10011010

If you see the bold part of the both sent and received bytes you can see that the number of bits changed is 2.

The two communicating devices are using a single-bit even parity check. Here there are two changed bits so this error will not be detected as this single bit even parity check scheme has a limit and it detects the error when the value of changed bit is odd but here it is even.

This parity scheme basically works well with the odd number of bit errors.

7 0
4 years ago
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