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irga5000 [103]
3 years ago
7

IMPORTANT...................... PLS HELP I REALLY NEED HELP WITH THIS ONE!!!!

Mathematics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

the formula is V=Bh,the second is a triangle, the volume is 96

Step-by-step explanation:

i got it right

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With a short time remaining in the​ day, a delivery driver has time to make deliveries at 7 locations among the 9 locations rema
kotegsom [21]
<h2>Answer:</h2>

The different possible routes are​ :

                           181440

<h2>Step-by-step explanation:</h2>

We are asked to find the number of different routes that are possible to choose  7 locations among the 9 locations remaining.

This means that we have to chose the locations and also we have to arrange them in different orders according to the different order of locations.

The method we have to use is a method of permutation.

When we have to chose and arrange r items out of a total of n items then the formula is given by:

n_P_r=\dfrac{n!}{(n-r)!}

Here we have: n=9

and r=7

Hence, the different possible routes are:

9_P_7=\dfrac{9!}{(9-7)!}\\\\\\9_P_7=\dfrac{9!}{2!}\\\\\\9_P_7=181440

       Hence, the answer is:

                  181440

5 0
3 years ago
You must be at least 42 inches tall to ride the bumper cars at an amusement park. Write an inequality that represents this situa
Anestetic [448]

Answer:

x is greater than or equal to 42 inches (I can't do the smybol for it)

Step-by-step explanation:

5 0
3 years ago
If I have 5 Orange Cats And 14 Black cats How many Cats Will there be left altogether and in colours if 2 Orange Cats get lost a
eimsori [14]

So, we will start by subtracting the orange cats

5-2=3 orange cats left

Then the black cats

14-6=8

Now we will add them back together:

8+3=11 Cats remaining

7 0
3 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
7 0
3 years ago
Which is equivalent to 80(1/4^x)
BabaBlast [244]
20/x ???
(By simplifying)
4 0
3 years ago
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