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natali 33 [55]
4 years ago
15

5x-4=-6x+4 then x=? please help!

Mathematics
2 answers:
kvasek [131]4 years ago
6 0

Step-by-step explanation:

5x+6x=4+4

11x=8

x=8/11

7nadin3 [17]4 years ago
4 0

Answer:

x = 8/11

Step-by-step explanation:

5x - 4 = -6x + 4

Collect like terms

5x + 6x = 4 + 4

11x = 8

x = 8/11

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Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7
meriva
The points where the 2 graphs intersect is  where x = 0 and x = 2.

-                 2                                  2
x   =    INT               x dA     /    INT        dA
                  0                                  0

INT dA   = INT -x^2 + 4x + 3 - (x^2 + 3 ) dx  =      INT -2x^2  + 4x
               =   -2 x^3/3 + 2x^2
               =   2.667  between 0 and 2

xdA  =   -2x^3 + 4x^2  INT xdA  =   -x^4/2 + 4x^3/3 = 2.667

centroid = 2.667 / 2.667  = 1  (x = 1)
3 0
4 years ago
Read 2 more answers
What is the value of x and y?
ladessa [460]

Answer:

x=16 and y=9

Step-by-step explanation:

2y+30=3y+21[Diagonals of parallelogram are equal]

30-21=3y-2y

y=9

3y=2x-5[Diagonals of parallelogram are equal]

3×9=2x-5

27=2x-5

2x=27+5

x=32/2=16

5 0
2 years ago
X + 4 = 40<br> X = 44<br><br> 23 = x - 6 <br><br> X = 29
valentinak56 [21]
1. X = 36

2. X = 29
7 0
1 year ago
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
What is the answer to this question
Lesechka [4]

Remark

There's a lot you don't know here. Are DE and GF parallel? Is B a right angle? You can't assume that it is. The safest way to proceed is to give x in terms of 58 and B. You might get an answer that gives you something like 32 but I don't think you can say that unless you are told somewhere that ABC is a right angle triangle with the right angle at B.

So what to do.

<BAC = 58o                               That's because <BAC = <IAK They vertically opposite.

<ABC + <BAC + <ACB = 180o       All triangles have 180o

<ACB = 180 - 58 - <ABC                Solve for an unknown angle of a triangle.

<ACB = 122 - <ABC

x = <ACB                                       Vertically opposite angles.

x = 122 - <ABC                             Answer  It's 32 if ABC is a right angle.  

6 0
4 years ago
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