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3 years ago

8

I need help plzzzzzz

1 answer:

AleksandrR [38]3 years ago

7 0

I believe the first one is 210
The party on Saturday was bigger. You know that Friday they had 31 people. Saturday they had 210 people.
The first one is 1+2(15)=31
The second one I’m not sure how to write up an equation for that because I just added 1+2+3+4+5..... and so on until 20 and got 210.
Not even sure if this is even right honestly, Just thought I’d at least try and help.

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4 0

3 years ago

the combined age of april and laura is 23 years. laura's age is two years more than half of april's age. what is laura's age

Kipish [7]

Laura's age is 9 years.

Solution:

Let x be the age of April.

Laura's age = 2 years more than half of April's age

<u>Convert statement into algebraic expression:</u>

Half of April's age = $\frac{x}{2}$

2 years more than half of April's age = $\frac{x}{2}+2$

Combined age of April and Laura = 23

⇒ April's age + Laura's age = 23

$$\Rightarrow \ \ x+(\frac{x}{2}+2) =23$

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$$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23$

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

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Denominators are same, now add the fractions.

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Do cross multiplication.

$$\Rightarrow \ \ 2x+x+4=23\times2$

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$$\Rightarrow \ \ 3x=42$

$$\Rightarrow \ \ x=14$

Aprils's age = 14 years

Laura's age = $\frac{14}{2}+2$

= 7 + 2

Laura's age = 9

Hence Laura's age is 9 years.

8 0

3 years ago