What is 152,909 rounded to the nearest hundred thousands

2 answers:

8 0

152,909 rounded to the nearest hundred thousands is 200,000.

Rules of rounding numbers
1) if the number being rounded off is followed by 0, 1, 2, 3, and 4, round the number down.
2) if the number being rounded off is followed by 5, 6, 7, 8, and 9, round the number down.

1 is the number on the hundred thousands place. It is followed by 5. We round 1 up to 2. Thus 2 is now in the hundred thousands place.

Alik [6]2 years ago

8 0

The answer is 200,000 because when you have 5-9 in the place value next to what your rounding to you go up a number in the place your rounding in and all the rest of the numbers behind the place value that your rounding in.

You might be interested in

Find the value of x round to the nearest tenth

Leto [7]

Answer:

58.6

Step-by-step explanation:

Use the formula $c=\sqrt{a^{2}+b^{2}$

solving for x (b)

$b=\sqrt{c^{2}-a^{2}$ = $\sqrt{61^{2}-17^{2}$ ≈58.58327

and 58.58327 rounds to 58.6

4 0

3 years ago

9. Convert 10,000 seconds into<br> hours

arlik [135]

Answer: 2.7777 hours

Step-by-step explanation: Here, we're asked to convert 10,000 seconds into hours.

Unfortunately, we don't have a conversion factor for seconds and hours. However, we know that 60 seconds = 1 minute and 60 minutes = 1 hour.

So we can convert 10,000 seconds into hours by using both of these conversion factors. Also, it's important to understand that when we go from a smaller unit, seconds, to a larger unit, hours, we divide.

So let's first convert 10,000 seconds into minutes by dividing 10,000 by the conversion factor, 60, to get 166.6666 minutes.

Next, we convert minutes to hours by dividing 166.6666 by the conversion factor, 60, to get 2.7777 hours.

So 10,000 seconds is approximately equal to 2.7777 hours.

8 0

3 years ago

Let f(x) = 1/x . Find the number b such that the average rate of change of f on the interval [2, b] is − 1/8

vekshin1

Answer:

b=4

Step-by-step explanation:

So, we have the function $f(x)=1/x$ . We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

f(2) = 1/(2) = 1/2

So, we have the point (2, 1/2)

At point b, f(b) = 1/b.

Let's plug this into the slope formula:

$\frac{y_2-y_1}{x_2-x_1}=\frac{.5-\frac{1}{b} }{2-b} =-1/8$

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

$\frac{.5b-1}{2b-b^2} =\frac{-1}{8}$