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grandymaker [24]
2 years ago
7

What is 152,909 rounded to the nearest hundred thousands

Mathematics
2 answers:
lara31 [8.8K]2 years ago
8 0
152,909 rounded to the nearest hundred thousands is 200,000.

Rules of rounding numbers
1) if the number being rounded off is followed by 0, 1, 2, 3, and 4, round the number down.
2) if the number being rounded off is followed by 5, 6, 7, 8, and 9, round the number down.

1 is the number on the hundred thousands place. It is followed by 5. We round 1 up to 2. Thus 2 is now in the hundred thousands place.


Alik [6]2 years ago
8 0
The answer is 200,000 because when you have 5-9 in the place value next to what your rounding to you go up a number in the place your rounding in and all the rest of the numbers behind the place value that your rounding in.
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Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
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