Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

So we apply chain rule:
=

Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
Answer:
a = 139.1
b = 56.2
Step-by-step explanation:
A. Reference angle = 68°
Opp = a
Hyp = 150
Therefore:
Sin 68 = opp/hyp
Sin 68 = a/150
150*sin 68 = a
a = 139.1 (nearest tenth)
B. Reference angle = 68°
Adj = b
Hyp = 150
Therefore:
Cos 68 = adj/hyp
Cos 68 = b/150
150*cos 68 = b
b = 56.2 (nearest tenth)
bearing in mind that the centroid in a triangle cuts each of the three medians in a 2:1 ratio.
since we know that A C = 12, let's split it in a 2:1 ratio then, cleary from the picture the larger is F C, so F C : A F is on a 2:1 ratio.

Answer:
Y = -3x - 1
Step-by-step explanation:
Y= mx + b
M is the slope
Y is the y intercept
You need to solve 5 equations
1. 7x - 2.1 = 14.1
2. 7x - 2.1 = 30.9 and so on
1. 7x - 2.1 = 14.1
7x = 16.2
x = 2.314 so first number in the domain is 2.314
You can calculate the other 4 in the same way