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3 years ago

Substract 10x +9 from 7x-10

1 answer:

5 0

This is a subtraction of expression. You should remember the rules in subtracting or adding expression. You can only add or subtract two terms if they are similar terms which mean they have the same variable with the same exponents.

(7x – 10) – (10x + 9)

You have to distribute the negative to the parenthesis.

7x – 10 – 10x – 9

7x – 10x – 10 – 9

-3x - 19

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3.40mol P2O5 to grams P2O5

Inessa05 [86]

<h3>Answer:</h3>

482.596 grams

<h3>Explanation:</h3>

The relationship between moles, molar mass and mass of a compound is given by;

$Moles =\frac{mass}{molar mass}$

In this case;

The compound in question is P₂O₅

Molar mass of P₂O₅ = 141.94 g/mol

Rearranging the formula;

Mass = Moles × molar mass

Therefore;

Mass of P₂O₅ = 3.4 mol × 141.94 g/mol

= 482.596 grams

Therefore, mass of P₂O₅ is 482.596 grams

5 0

4 years ago

In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol).Calculate the number of moles of chlo

sveticcg [70]

1 mole = 70.9
X mole = 140
X=1.9746 moles
X= 1.98 when rounded to 3 significant figures.

4 0

3 years ago

Read 2 more answers

What is the force that will make the motion of the wooden block and the ice cube stop?

Usimov [2.4K]

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3 years ago

A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t

gladu [14]

<u>Solution</u> : Emperical Formula = $CH_{3}$

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

20.0g Hydrogen

First convert the given masses into moles.

$80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}$

$20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}$

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

$\frac{6.66}{6.66}\text{mole of C}= 1$

$\frac{20.0}{6.66}\text{mole of C}= 3$

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula = $CH_{3}$

3 0

4 years ago

Formal charge of Cl in CHCl3

Vsevolod [243]

FC(C) = 4 - 0.5*8 - 0 = 0) FC(Cl) = 7 - 0.5*2 - 6 = 0

6 0

3 years ago