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VikaD [51]
3 years ago
8

A temperature of 273 K is the temperature at which water A. evaporates. B. is at its densest. C. freezes. D. boils.

Chemistry
2 answers:
Irina-Kira [14]3 years ago
8 0
C. freezes
Pure water freezes at 273 Kelvin<span> and boils at </span>373 Kelvin<span>.</span>
julsineya [31]3 years ago
5 0

A temperature of 273 K is the temperature at which water

A. freezes.

B. boils.

C. is at its densest.

D. evaporates.

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If you determine the molar heat of neutralization for an acid is 49.1 kJ/mol and the accepted value is found to be 55.2 kJ/mol,
zhenek [66]

Answer: % Errror = 11.05%

Explanation:

Percentage error is the difference between the measured value and the theoretical value as expressed in percent.

That is;

% Error =

( Theoretical value -measured value) /(Theoretical value) × 100

Theoretical value =55.2kJ

Measured value = 49.1kJ

% Error = (55.2-49.1)/(55.2) ×100

%Error = 6.1/55.2 ×100

% Error = 0.1105 ×100

% Error = 11.05

Therefore the percentage error is 11.05%

5 0
3 years ago
How does electronegativity cause the polarity in water and, ultimately, enable water to form hydrogen bonds between other water
gulaghasi [49]
Oxygen is more <u>electronegative</u> than Hydrogen 
                                  So . . . 
When the two form covalent bonds, oxygen pulls the electrons closer and farther from hydrogen
                                   So . . .
The water molecule is <u>polar</u>, with oxygen more negative and hydrogen more positive.
                                   So . . .
Since opposites attract, the more negative oxygens attract the more positive hydrogens of other water molecules, forming the <u>hydrogen bonds.</u>
6 0
4 years ago
An example of a colloid which is composed of a liquid dispersed in a gas would be
Aleksandr-060686 [28]
Any colloid consisting of a solid dispersed in a gas is called a smoke. A liquid dispersed in a gas is referred to as a fog. So the answer would be smoke
6 0
3 years ago
Determine the number of particles in 0.332 g of NaCl (molar mass NaCl=58.44 g/mol).
ira [324]

Answer:

3.42×10²¹ of particles

Explanation:

To determine the number of particles we should know, that:

1 mol of anything contains 6.02×10²³ particles

Therefore we have to find out, how many moles corresponds to 0.332 g of NaCl.

The conversion is: 0.332 g / 58.44 g/mol = 0.00568 moles

The rule of three to determine the number of particles is:

1 mol of NaCl has 6.02×10²³ particles

0.00568 moles must have (0.00568 . 6.02×10²³ particles )/1 = 3.42×10²¹

8 0
3 years ago
A doppler radar sends a pulse at 6.00x10^9 hz. it reflects off some clouds, and returns to the radar 672 hz higher. what is the
ipn [44]

Answer:

v-rel = 16.8

Make sure to read the explaination so you can solve it yourself!

Explanation:

I had this same question on Acellus, here is how I answered it:

Equation being used:   Δf = 2*fο*vrel/c

( this equation can be found in the  bottom of the lesson manual in the help tab)

Where,

Δf = change in frequency; 672

fο = frequency before being doppler shifted; 6.00 * 10^9

vrel = relative velocity; unknown

c = speed of light; 3.00 * 10^8

Now that we have written the numbers we know down, we must rearrange the equation for the velocity (vrel)

Starting Equation:

Δf = 2*fο*vrel/c

Multiply by c, then divide by 2fo to isolate vrel.

This will leave us with the equation:

Δfc/2fo, now we plug in the numbers

(672 * (3*10^8)) / (2* (6.00*10^9))

Once we plug this into the calculator, you should get

16.8

I hope this helped you, Wawawewa!

8 0
2 years ago
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