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aalyn [17]
3 years ago
12

Is Pb(NO3)2 soluble or insoluble?

Chemistry
1 answer:
Sedaia [141]3 years ago
4 0

Answer: it is soluble

Explanation: nitrates are soluble.

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What must ALWAYS be used to convert between quantities of two different chemical substances?
Vedmedyk [2.9K]

Answer:

Balanced equations and mole ratios

In general, mole ratios can be used to convert between amounts of any two substances involved in a chemical reaction.

Explanation:

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2 years ago
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Which events occurred during the space race
Roman55 [17]

Answer:

Date Significance Soviet Union Mission

August 21, 1957 First intercontinental ballistic missile (ICBM) R-7 Semyorka

October 4, 1957 First artificial satellite First signals from space Sputnik 1

November 3, 1957 First dog in orbit (Laika) Sputnik 2

January 31, 1958 First US satellite, detection of Van Allen radiation belts

Explanation:

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3 years ago
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What is always true of an object with a lit of mass ?
sertanlavr [38]

Such an object makes a larger dent in the fabric of space-time than an object with little mass. (It has a greater gravitational attraction than less massive objects)

A greater force is required to accelerate such an object than a less massive object

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3 years ago
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The reaction of NO2 with ozone produces NO3 in a second-order reaction overall.
Brilliant_brown [7]

Answer :  The rate of reaction is,

Rate=4.77\times 10^{-19}M/s

The appearance of NO_3 is, 4.77\times 10^{-19}M/s

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

NO_2(g)+O_3(g)\rightarrow NO_3(g)+O_2(g)

The rate law expression will be:

Rate=k[NO_2][O_3]

Given:

Rate constant = k=1.69\times 10^{-4}M^{-1}s^{-1}

[NO_2] = 1.77\times 10^{-8}M

[O_3] = 1.59\times 10^{-7}M

Rate=k[NO_2][O_3]

Rate=(1.69\times 10^{-4})\times (1.77\times 10^{-8})\times (1.59\times 10^{-7})

Rate=4.77\times 10^{-19}M/s

The expression for rate of appearance of NO_3 :

\text{Rate of reaction}=\text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}

As, \text{Rate of reaction}=4.77\times 10^{-19}M/s

So, \text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}=4.77\times 10^{-19}M/s

Thus, the appearance of NO_3 is, 4.77\times 10^{-19}M/s

7 0
3 years ago
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stiks02 [169]
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4 0
2 years ago
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