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Soloha48 [4]
3 years ago
5

Which equation represents an exponential function with an initial value of 500?

Mathematics
1 answer:
Georgia [21]3 years ago
8 0

Answer: C

Step-by-step explanation:

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What is the answer to the equation -0.5x+1.75x<-1.75+2.75x
PIT_PIT [208]
X>7/6
Combine like terms
Subtract 2.75x from both sides
Combine like terms
Divide -1.5 from both sides

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What is the answer for -8n=13
KatRina [158]

Answer:

-13/8

Step-by-step explanation:

u divied by -8 to get n by itself

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3 years ago
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The product of a 7 and a number.
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it would look like this: x times 7 -> 7x

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3 years ago
Identify the law illustrated by: 5n x 1 is the same as 5n
tangare [24]

<u><em>The law illustrated is Distributive Law</em></u>

This question is under a topic called algebra laws.

The laws are;

- Commutative law; This implies that when we are to add or multiply numbers, the order of addition or multiplication doesn't matter as we will still get same result.

- Associative law; This implies that if we want to add more than 2 numbers, if we decide to add the first 2 before adding the third one, we will still get the same result as if we added the second one to the third one before adding to the first one. This law also applies to multiplication.

- Distributive law; This implies that when two numbers are multiplied to produce a result, both numbers are factors of the result.

We are told in the question that ; 5n x 1 = 5n

This means that 5n and 1 are factors of 5n and this corresponds to distributive law

Read more at; brainly.in/question/39479409?tbs_match=1

7 0
2 years ago
Can predictions be made of a scatterplot that shows no association? explain your answer.
hichkok12 [17]
<span>No, you can't make a prediction from a scatter plot that doesn't show any associations. There have to be associations in order to form a trend. If there is no trend, there is no way to make a prediction. A scatter plot is similar to a line graph where you can mark the appropriate data points in order to see if a trend is developing.</span>
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3 years ago
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