There are three questions related to this problem.
First, the probability of the mail will arrive after 2:30
PM
<span>Find the z-score of 2:30 which is 30 minutes after 2:00.</span>
<span>
z(2:30) = (2:30 – 2:00)/15 = -30/15 = -2</span>
<span>
P(x < 2:30) = P(z<-2) = 0.0228</span>
<span>
</span>
Second, the probability of the mail will arrive at 1:36
PM
<span>Find the z-score of 1:36 which is 24 minutes before 2:00.</span>
<span>
z(1:36) = (1:36 – 2:00)/15 = -24/15 = -1.6</span>
<span>
P(x < 1:36) = P(z<-1.6) = 0.0548</span>
Lastly, the probability of the mail will arrive between 1:48
PM and 2:09 PM
Find the z-score of 1:46 and 2:09 PM which will result to
a z value of 0.034599
<span>P(1:48 < x < 2:09) = P(z<0.034599) = 0.5138</span>
Answer:
57
Step-by-step explanation:
408-9 =399
399/7 =57
the length of the shorter side is:L = 13.125cm
<h3>
how long will the shorter side be?</h3>
In the longer side we have 8 segments.
We know that the side measures 35 cm, then each one of the 8 segments measures:
35cm/8 = 4.375cm
Now, we can see that in the shorter side we have 3 of these segments.
Then the length of the shorter side is:
L = 3*(4.375cm) = 13.125cm
If you want to learn more about lengths:
brainly.com/question/2217700
#SPJ1
The answer is going to be 0.55555556. hope that helped
