The sampling distribution of x has a mean μₓ = <u> μ </u> and standard deviation σₓ = <u> σ/√n </u>.
In the question, we are given that a random sample of size n is drawn from a large population with mean μ and standard deviation σ.
We are asked to find the mean and the standard deviation for the sampling distribution of the variable x for this sample.
The sample mean is regularly distributed, with a mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size, for samples of any size taken from populations that have a normal distribution.
Thus, the sampling distribution of x has a mean μₓ= <u> μ </u> and standard deviation σₓ= <u> σ/√n </u>.
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The provided question is incomplete. The complete question is:
"Fill in the blanks to correctly complete the sentence below.
Suppose a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ.
The sampling distribution of x has mean μₓ =______ and standard deviation σₓ =______."
<span>A. to use algebraic methods to solve geometric problems.
</span>
2a+3=s
I used the first letter of the name, or you can use x and y in place of a and s
1.
18.98 per 1000
320,000 / 1000 = 320
18.98 x 320 = $6073.60
2. smoker: 9.36 * 100 = 936
non smoker: 7.85 * 100 = 785
936 - 785 = $151
