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2 years ago

Graph the solution for the following linear system x+y>0 x+y+5<0

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

5 0

Undefineeddd, calculator said so.

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Imagine that city officials in your hometown expect a huge rise in population over the next few years. Which of the following pe

ioda

Answer:

C an urban planner

Step-by-step explanation:

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3 years ago

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F(x) = 4x2 + 1 and g(x) = x2 - 5, find (f+ g)(x)

inn [45]

Answer:

Step-by-step explanation:

(f + g)x translates into a more readable f(x) + g(x) so all you do is

f(x) + g(x) = 4x^2 + 1 + x^2 - 5

f(x) + g(x) = 5x^2 - 4

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2 years ago

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What is 2x-64<108 If you answer this I will give you a total of 23 points!

alexandr1967 [171]

Answer:

2x-64<108

One solution was found :

x < 86

Rearrange:

Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :

2*x-64-(108)<0

Step by step solution :

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

2x - 172 = 2 • (x - 86)

Equation at the end of step 1 :

Step 2 :

2.1 Divide both sides by 2

Solve Basic Inequality :

2.2 Add 86 to both sides

x < 86

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2 years ago

Can y’all help me with it pls

Marta_Voda [28]

Answer:

1. D

2. C

3. C, A F

Step-by-step explanation:

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2 years ago

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one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola

omeli [17]

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

$x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1$ .

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

$x_1 + x_2 = \frac{-b}{a}$

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

$x_1 \cdot x_2 = \frac{c}{a}$

These relations between the solutions give us a brief idea of what the solutions should be like.

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3 years ago