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Makovka662 [10]
2 years ago
10

The following display from a TI-84 Plus calculator presents a 99% confidence interval for a proportion.Fill in the blanks: We ar

e ________ confident that the population mean is between _______ and _______.a) 1%, 0, 0.583120b) 99%, 0, 0.583120c) 99%, 0.385631, 0.780609d) 1%, 0.385631, 0.780609
Mathematics
1 answer:
vladimir2022 [97]2 years ago
7 0

Answer:

The following display from a TI-84 Plus calculator presents a 99% confidence interval for a proportion.Fill in the blanks:

We are ____99%____ confident that the population mean is between ___0.385631____ and ___0.780609____.

c) 99%, 0.385631, 0.780609

Step-by-step explanation:

This is the only correct option, given the relevant population mean range.  Option B is not correct as the population mean cannot range between 0 and 0.583120 as given by the option.  Options 'a' and 'd' are not relevant to the question because they have 1% confidence level, instead of the stated 99% confidence level.

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Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125
liq [111]

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

3 0
10 months ago
1. Use a property of exponents to write (3b)⁵ as a product of powers. 2. What is the width of the rectangle written as an expone
motikmotik

Answer:

Step-by-step explanation:

1. (3b)^5

= (3b)^2 * (3b)^3.

2.  Width = area / length

= 10^4 / 10^3

= 10^(4-3)

= 10 m.

8 0
3 years ago
sandy had 10 dollars in her collection. she gave 3 to her younger sister. her parents were so impressed that they quadrupled her
pantera1 [17]
(10-3)*4

Hope this helps!
7 0
3 years ago
Read 2 more answers
(a) (x+3)(x+2) =<br><br><br> How do I solve this without the use of parentheses
Ierofanga [76]

Answer: x^2+5x+6

Step-by-step explanation:

5 0
3 years ago
ANSWER NOW FOR A LOT OF POINTS!
sleet_krkn [62]
Answer: x>2
Explanation:
4x- 2>6
4x>8
x> 2
HOPE IT HELPS!!!:):)
3 0
2 years ago
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