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Otrada [13]
3 years ago
15

Please help me with number 2 please

Mathematics
2 answers:
andreev551 [17]3 years ago
6 0
The answer is 43.8444444
Pani-rosa [81]3 years ago
5 0
The answer to question 2 is43.844444
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I’m new to this app and I need help with those two questions please help!!
larisa86 [58]

y=x²-10x-7

a>0 so we will be looking for minimum

x=-b/2a=10/2=5

y=25-50-7=-32

Answer: (5;32)

y=-4x²-8x+1

а<0 so we will be looking for maximum

х=-b/2a=8/-8=-1

у=4+8+1=13

Maximum point (-1;13)

6 0
3 years ago
Sorry bout that, THIS IS THE NEW ONE PLEASE ANSWER
Sergio039 [100]

Answer:

Step-by-step explanation:

Putting value of y = 5

4(5)2 - 7(5) - 6

4(25) - 35 - 6

100 - 41

59

3 0
3 years ago
What is the range of the function f(x) = 2x+3
MrRissso [65]

Answer: (-∞,∞)

Step-by-step explanation: The line extends forever in both directions meaning that the endpoints will be negative infinity and infinity.

3 0
3 years ago
Damian plans to do a lot of babysitting this summer. He charges $6.50 per hour and babysits for 3 hours. He has agreed to babysi
RoseWind [281]

Answer:

$195

Step-by-step explanation:

multiplying 6.50*3*10 = 195

7 0
3 years ago
Read 2 more answers
Please help and explain
Murrr4er [49]

Answer: Option A

x=\frac{3+i}{2} or x=\frac{3-i}{2}

Step-by-step explanation:

Use the quadratic formula to find the zeros of the function.

For a function of the form

ax ^ 2 + bx + c = 0

The quadratic formula is:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case the function is:

2x^2-6x+5=0

So

a=2\\b=-6\\c=5

Then using the quadratic formula we have that:

x=\frac{-(-6)\±\sqrt{(-6)^2-4(2)(5)}}{2(2)}

x=\frac{6\±\sqrt{36-40}}{4}

x=\frac{6\±\sqrt{-4}}{4}

Remember that \sqrt{-1}=i

x=\frac{6\±\sqrt{4}*\sqrt{-1}}{4}

x=\frac{6\±\sqrt{4}i}{4}

x=\frac{6\±2i}{4}

x=\frac{3\±i}{2}

x=\frac{3+i}{2} or x=\frac{3-i}{2}

3 0
3 years ago
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