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sineoko [7]
3 years ago
8

Log33 + log327 simplify if possible

Mathematics
1 answer:
alexgriva [62]3 years ago
8 0
Log360 is your answer.
Good luck on what ever your on!!!!!!!!
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The tables represent the functions f(x) and g(x).
dolphi86 [110]

A function assigns the values. The correct option is C, x=-6.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

A.) When the value of x is -12,

f(-12) = 2/3(-12) + 7 = -1

g(-12) = 2(-12) + 15 = -9

B.) When the value of x is -9,

f(-9) = 2/3(-9) + 7 = 1

g(-9) = 2(-9) + 15 = -3

C.) When the value of x is -6,

f(-6) = 2/3(-6) + 7 = 3

g(-6) = 2(-6) + 15 = 3

D.) When the value of x is -3,

f(-9) = 2/3(-3) + 7 = 5

g(-9) = 2(-2) + 15 = 11

Hence, the correct option is C, x=-6.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

4 0
2 years ago
|6-27| how the answer this question
sweet [91]

Answer:

First notice that they’re asking for the absolute value of the equation.

The absolute value is how far that number is from 0.

Basically it’s the number without a negative sign.

ok so 6-27 = -21

The product for 6-27 (21) is 21 spaces away from 0.

|6-27| = 21

21 is the answer to your question.

Hope this helped and pls mark me brainliest if it did :)

7 0
3 years ago
Read 2 more answers
Tomas reparte 9 kg de mandarinas en mallas de tres cuartos de kilo cada una . ¿Cuantas mallas obtiene?
MrRissso [65]

Responder:

12

Explicación paso a paso:

Dado que:

Kilogramo total de mandarina = 9 kg

Tamaño de cada distribución = 3/4 de kilo

Número de mallas:

Kilogramo / tamaño total por distribución

9 kg ÷ 3/4 kg

9 * 4/3

= (9 * 4) / 3

= 36/3

= 12

7 0
3 years ago
Sugar was traditionally produced and sold as sugarloaves, which are cones of sugar wrapped in paper. Find the total surface area
Zolol [24]

Answer:

A = 326,73 cm²

Step-by-step explanation:

The area of a circular cone is area of the base (A₁ ) plus area lateral ( area of a circular sector of radius the slant height )

Then we proceed to calculate the area of the base A₁

diameter of circular base is 8 cm then the radius is 4 cm and the area is:

A₁ = π*r²  =  3,14* (4)²

A₁ = 3,1416*16   =  50,2656 cm²

Now Lateral area of the cone (A₂) is equal to the area of a circular sector with radius the slant height. We will calculate it, taken into account that this circular sector is part of a circle of radius the slant height.

Between the area of circular sector with radius the slant height and the area of the circle with the same radius there is a linear relation. That is we can calculate area of a circular sector by rule of three as follows:

The length of the circular sector is the length of the circle of the base of the cone, that is:

L = 2*π*(4)

L = 2*3,1416*4

L = 25,1328 cm

Then we have a circular sector of length 25,1328 cm

The area of the circle of radius 22 cm is:

A(c)  = π*(22)²     ⇒   A(c)  = 1520,5344 cm²

And the length of this circle is:

L(c)  =  2*π*(22)     ⇒   138,2304 cm

Then we apply a rule of three

For a length of      138,2304 cm  ⇒⇒⇒  (area)  1520,5344 cm²

Then for a length of  25,1328 cm   ⇒⇒⇒(area)   A₂ (??)

Therefore:

A₂ =  (25,1328)*1520,5344)/ 138,2304

A₂ = 276,4608 cm²

Then total area of the cone is:

A = A₁  +  A₂

A =  50,2656  +276,4608

A  = 326,7264 cm²

Round answer  A = 326,73 cm²

8 0
3 years ago
Read 2 more answers
What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
LenKa [72]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

5 0
3 years ago
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