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3 years ago

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The domestic postage rate for first-class letters weighing 12 oz or less is $0.37 for the first ounce and $0.23 for each additio

nal ounce or part of an ounce. How much will it cost to send a letter that weighs 7.5 oz?

1 answer:

tatyana61 [14]3 years ago

5 0

The letter will cost $1.98.

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Gavin goes for a run at a constant pace of 9 minutes per mile. Ten minutes later, Lars goes for a run, along the same route, at

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Answer: The answer is 35 minutes.

Step-by-step explanation: Given that Gavin goes for a run at a constant pace of 9 minutes per mile and after 10 minutes, Lars started running along the same route, at a constant pace of 7 minutes per mile. We need to find the number of minutes Lars will take to reach Gavin.

In 9 minutes, distance run by Gavin = 1 mile.

So, in 1 minute, distance travelled by Gavin will be

$d_G=\dfrac{1}{9}=\dfrac{7}{63}~\textup{miles}.$

Similarly,

In 7 minutes, distance run by Lars = 1 mile.

So, in 1 minute, distance travelled by Lars will be

$d_L=\dfrac{1}{7}=\dfrac{9}{63}~\textup{miles}.$

Now, since Lars started after 10 minutes, so distance run by Gavin in those 10 minutes will be

$d_{G10}=\dfrac{10}{9}=\dfrac{70}{63}~\textup{miles}.$

Now, difference between Lars and Gavin's rate of runnings is

$\dfrac{9}{63}-\dfrac{7}{63}=\dfrac{2}{63}.$

Therefore, the time taken by Lars to reach Gavin is given by

$t=\dfrac{\frac{70}{63}}{\frac{2}{63}}=35.$

Thus, the required time is 365 minutes.

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It doesnt differ lets take 10 = 6 + 4 multiply thru by a negative and flip the sign -10 = -6 - 4 flipping an equals sign about seems redundant, but the process works nonetheless <span>having two separate rules for solving inequalities and equalities seems pointless

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You got this

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