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tino4ka555 [31]
3 years ago
13

Marble is a _____ metamorphic rock. banded foliated nonfoliated folded

Biology
2 answers:
Whitepunk [10]3 years ago
7 0
Non-foilated metamorphic rock?? maybe
Natasha2012 [34]3 years ago
4 0

Answer: Non-foliated

Explanation: Metamorphic rocks have been modified by many factors that converts it into various forms.

These factors are chemical processes, pressure and heat. Exposure to such conditions has changed its mineralogy.

Marble is an example of Non-Foliated metamorphic. They do not have layered or banded apperance.

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Which shot angle rarely results in a clean kill, ruins a lot of meat, and provides an animal the best opportunity to detect the
GarryVolchara [31]
<span>A head-on shot rarely results in a clean kill, ruins meat, and provides a means for the animal to best detect the hunter. It is difficult to achieve this shot, which often results in the deer hearing the gun and running away (thus, detecting the hunter). Moreover, the shot will cause in a waste of a lot of the meat because of the location rendering it unusable and inedible.</span>
3 0
3 years ago
Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004
Simora [160]

Hardy Weinberg Equilibrium

Explanation:

  • Hardy Weinberg Equilibrium formula for allelic frequency is: p+q=1
  • Hardy Weinberg Equilibrium formula for genotypic frequency is: p^2+q^2+2pq=1
  • Here,p=frequency of dominant allele

                 q=frequency of recessive allele

                 p^2=frequency of dominant genotype

                 q^2=frequency of recessive genotype

                 2pq=frequency of heterozygous genotype

  • frequency of affected individuals=0.0004(given)

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as:     q^2=0.0004

  • If q^2=0.0004 q will be 0.02;frequency of recessive allele will be 0.02
  • Using the formula p+q=1

                                       p+0.02=1\\p=1-0.02=0.98

  • hence,frequency of dominant allele will be 0.98
  • Frequency of dominant genotype will be p^2=(0.98)^2=0.9604
  • Frequency of heterozygous genotype will be 2pq=2*0.98*0.02=0.0392

7 0
3 years ago
A simplified model of the human blood-type system has four blood types: a, b,ab and o. thereare two antigens, anti-a and anti-b.
Kay [80]
First calculate the probability of type AB, which is the remainder after subtracting types A, B and O.

P(AB) = 1-(0.34+0.12+0.5) = 1-0.96 = 0.04

Anti-b will react with types B and AB, so 
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Answer: For this person, the probability of reaction with anti-b is 0.16
8 0
3 years ago
Predict what the calf produced in a union between each of these parents might look like. Explain your answers.
Charra [1.4K]
We know that purebred means that the organism contains the same alleles for the trait and hybrid means that it contains two different alleles for the trait. Dominant means that it will be shown in a hybrid and a purebred, but recessive traits will only be shown in purebred recessive organisms.

a) The offspring of a purebred white (recessive) cow and a purebred brown (dominant) bull, would be all hybrid brown (dominant). This is because as I stated above, dominant traits are shown when the offspring has both dominant and recessive alleles for the same trait.

b) The offspring of a purebred brown (dominant) cow and a purebred brown (dominant) bull would all be purebred brown (dominant). This is because if both of the parents have only alleles that code for brown color, the only color that the offspring can be is brown.

c) The offspring of a purebred white (recessive) cow and a purebred white (recessive ) bull would all be purebred white (recessive), for the same reason stated above in part b), the only difference being that the alleles are recessive and code for white color instead of being dominant and coding for brown color.

d) The offspring of a hybrid brown (dominant) cow and a purebred white (recessive) bull would be half hybrid brown (dominant) and half purebred white (recessive). This can be seen best if you set up a Punnett Square, which is a diagram that shows allele frequencies in offspring. This shows you that the chance that the offspring get the dominant allele from the mother cow is 50%, thus 50% would be hybrid brown (dominant), as the father can contribute only a recessive white allele. The other 50% would be purebred white (recessive) because the mother cow would be contributing a white allele and so would the father.

Hope this helps! :)
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"Water depth" is the factor among the choices given that has the <span>greatest importance in determining the characteristics of an aquatic ecosystem. The correct option among all the options given is the second option.
</span>
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3 years ago
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