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icang [17]
3 years ago
13

The range of the function f(x)=x+5 is (7,9). What is the function's domain?

Mathematics
1 answer:
Jlenok [28]3 years ago
5 0
The function is : f ( x ) = x + 5 
If the range is ( 7, 9 ) we have to find the domain.
7 = x 1 + 5
x 1 = 7 - 5 = 2
9 = x 2 + 5 
x 2 = 9 - 8 = 4
Answer:
The domain is : A )  ( 2, 4 ) 
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<img src="https://tex.z-dn.net/?f=%20%7B%28%20%5Cfrac%7B5%7D%7B3%7D%20%29%7D%5E%7B2n%20%2B%201%7D%20%20%7B%28%20%5Cfrac%7B5%7D%7
Alisiya [41]

Answer:

n = -4

Step-by-step explanation:

(\frac{5}{3} )^2^n^+^1 * (\frac{5}{3} )^5 = (\frac{5}{3})^n^+^2

in multiplication if the base are same u can add there exponent.

(\frac{5}{3})^2^n^+^1^+^5 = (\frac{5}{3})^n^+^2

base of both sides are equal so their exponent will be equal

2n + 1 + 5 = n + 2

2n + 6 = n + 2

2n - n = 2 - 6

n = -4

5 0
2 years ago
D = 10.2 ft, r = 0.5 ft/h find t
Margaret [11]

Answer:

20.4

Step-by-step explanation:

If you are using D = r × t

                          10.2 = 0.5(t)

                           10.2/0.5 = t

                            20.4 = t

7 0
2 years ago
Royston and his friends toss a paper cup to see how it lands. They repeat this experiment 60 times and record the results in a t
fgiga [73]

Answer:

The real answer is d

Step-by-step explanation:

8 0
3 years ago
Simplify each expression (2a^4)^-3, a ≠ 0
sweet-ann [11.9K]

Answer:

1/(8a^12)

Step-by-step explanation:

(2a^4)^-3

Rewriting

2^-3  * a^4^-3

We know  x^y^z = x^(y*z)

2^-3 * a^(4*-3)

2^-3 * a^-12

We know x^-y = 1/a^y

1/2^3  * 1/a^12

1/8 * 1/a^12

1/(8a^12)

8 0
2 years ago
Which of these numbers round to 6.81 nearest hundredth
vova2212 [387]

Answer:

6.81

Step-by-step explanation:

If the last digit in the fractional part of 6.810 is less than 5, then simply remove the last the digit of the fractional part.

8 0
3 years ago
Read 2 more answers
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