Answers:
- a) x = 9
- b) arc JK = 68
- c) arc MJ = 112
- d) arc LMK = 248
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Explanation:
Arcs JK and KL form a semicircle, so they add to 180 degrees
(arcJK) + (arcKL) = 180
(5x+23) + (17x-41) = 180
22x-18 = 180
22x = 180+18
22x = 198
x = 198/22
x = 9
Then you'll use this x value to find arc JK and arc KL
arc JK = 5x+23 = 5*9+23 = 68
arc KL = 17x - 41 = 17*9-41 = 112
Since central angles MNJ and KNL are vertical angles, this means minor arcs MJ and KL are congruent arcs. So arc MJ is also 112 degrees
Arc LMK is basically nearly everything of the full circle, but we exclude out the portion from L to K (the shorter distance)
arc LMK = (full circle) - (measure of minor arc LK)
arc LMK = 360 - 112
arc LMK = 248
X + 9 = 2x - 3
<u>-x -x </u>
9 = x - 3
<u> +3 +3</u>
12 = x
X=3y+4, y=y
x+y=180, 3y+4+y=180, 4y+4=180
4y+4=180
4y=176
y=44
x=3(44)+4, x=132+4, x=136
(I am not a very good artist in this case:)
Answer:
Step-by-step explanation:
<h3><u>Given:</u></h3>
y = 12 cm
θ = 24°
Using trigonometric ratio, tan.
![\displaystyle \boxed{tan \theta = \frac{opposite}{adjacent} }\\\\tan \ 24 = \frac{x}{12} \\\\0.445 = \frac{x}{12} \\\\Multiply \ 12 \ to \ both \ sides\\\\0.445 \times 12 = x\\\\5.3 = x\\\\x = 5.3\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7Btan%20%5Ctheta%20%3D%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20%7D%5C%5C%5C%5Ctan%20%5C%2024%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5C0.445%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5CMultiply%20%5C%2012%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C0.445%20%5Ctimes%2012%20%3D%20x%5C%5C%5C%5C5.3%20%3D%20x%5C%5C%5C%5Cx%20%3D%205.3%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Let
x = first consecutive odd
x + 2 = second consecutive odd
Based on the problem, we equate
x + (x + 2) = 32
Solving for x,
2x + 2 = 32
2x = 32 - 2
2x = 30
x = 30/2
x = 15
and x + 2 = 15 + 2 = 17
Therefore, the integers are 15 and 17.
