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Kisachek [45]
3 years ago
15

Is the shape in the picture a square or a rectangle??? To me it looks like a square.

Mathematics
2 answers:
-BARSIC- [3]3 years ago
7 0
It looks like a rectangle
mestny [16]3 years ago
3 0
The picture is a rectangle, as you can see if you were to look closely at the picture. You can tell because of the x-axis and the y-axis
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Principal Zimmer wants to make sure that students have enough time to get across campus between classes. To see how long it take
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the answers is step 3

Step-by-step explanation:

i took the test

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The price of a television set on sale is $360. This is two thirds of the regular price.find the regular price.
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divide 360 by 2 with an outcome of 180 then multiply by 3
answer is 540
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Emma has 7 bottles: 3 bottles that contain juice, 2 bottles
UNO [17]

Answer: Out of 7 bottles, 2 bottles contain soda. This means that 2 bottles= 29% out of 100%. 7/2 (7 divided by 2) = 0.285. 0.285 can be rounded up to 0.29, meaning that the approximate percentage of the bottles that contain soda is 29%.

4 0
4 years ago
Anyone know how to do this with a explanation ?
storchak [24]

Answer:

30 degrees

Step-by-step explanation:

Since we know that all triangles equal 180 degrees, we can add the 2 given angles and subtract that from 180 to find the remaining angle.

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8 0
3 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
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